Реши уравнения: а) 2/7x = 2 2/7

Решаю уравнения по порядку: а) $\frac{2}{7}x = 2\frac{2}{7}$ $\frac{2}{7}x = \frac{16}{7}$ $x = \frac{16}{7} \cdot \frac{7}{2}$ $x = 8$ б) $\frac{3}{5}y = 2\frac{9}{10} - \frac{1}{5}$ $\frac{3}{5}y = \frac{29}{10} - \frac{2}{10}$ $\frac{3}{5}y = \frac{27}{10}$ $y = \frac{27}{10} \cdot \frac{5}{3}$ $y = \frac{9}{2} = 4\frac{1}{2}$ в) $\frac{3}{7}a + \frac{2}{5} = 1$ $\frac{3}{7}a = 1 - \frac{2}{5}$ $\frac{3}{7}a = \frac{3}{5}$ $a = \frac{3}{5} \cdot \frac{7}{3}$ $a = \frac{7}{5} = 1\frac{2}{5}$ г) $3\frac{1}{3} : k = 1\frac{1}{3} : 2$ $\frac{10}{3} : k = \frac{4}{3} : 2$ $\frac{10}{3} : k = \frac{2}{3}$ $k = \frac{10}{3} : \frac{2}{3}$ $k = 5$ д) $y : 1\frac{1}{2} = 2\frac{1}{3} \cdot \frac{1}{3}$ $y : \frac{3}{2} = \frac{7}{3} \cdot \frac{1}{3}$ $y : \frac{3}{2} = \frac{7}{9}$ $y = \frac{7}{9} \cdot \frac{3}{2}$ $y = \frac{7}{6} = 1\frac{1}{6}$ е) $\frac{2}{7}x + \frac{3}{7}x = 2\frac{7}{14}$ $\frac{5}{7}x = \frac{35}{14}$ $\frac{5}{7}x = \frac{5}{2}$ $x = \frac{5}{2} \cdot \frac{7}{5}$ $x = \frac{7}{2} = 3\frac{1}{2}$ ж) $m + \frac{3}{8}m = \frac{1}{4}$ $\frac{11}{8}m = \frac{1}{4}$ $m = \frac{1}{4} \cdot \frac{8}{11}$ $m = \frac{2}{11}$ з) $y - \frac{2}{9}y = 4\frac{2}{3}$ $\frac{7}{9}y = \frac{14}{3}$ $y = \frac{14}{3} \cdot \frac{9}{7}$ $y = 6$ и) $\frac{2}{5}z + \frac{2}{3}z - \frac{7}{15}z = 2\frac{1}{2}$ $\frac{6}{15}z + \frac{10}{15}z - \frac{7}{15}z = \frac{5}{2}$ $\frac{9}{15}z = \frac{5}{2}$ $\frac{3}{5}z = \frac{5}{2}$ $z = \frac{5}{2} \cdot \frac{5}{3}$ $z = \frac{25}{6} = 4\frac{1}{6}$ к) $3\frac{1}{2} \cdot (\frac{2}{3}x + \frac{4}{7}) = 2\frac{1}{3}$ $\frac{7}{2} \cdot (\frac{2}{3}x + \frac{4}{7}) = \frac{7}{3}$ $\frac{2}{3}x + \frac{4}{7} = \frac{7}{3} \cdot \frac{2}{7}$ $\frac{2}{3}x + \frac{4}{7} = \frac{2}{3}$ $\frac{2}{3}x = \frac{2}{3} - \frac{4}{7}$ $\frac{2}{3}x = \frac{14}{21} - \frac{12}{21}$ $\frac{2}{3}x = \frac{2}{21}$ $x = \frac{2}{21} \cdot \frac{3}{2}$ $x = \frac{1}{7}$ л) $(\frac{5}{8}x - \frac{1}{5}) \cdot \frac{3}{4} = \frac{3}{4}$ $\frac{5}{8}x - \frac{1}{5} = \frac{3}{4} : \frac{3}{4}$ $\frac{5}{8}x - \frac{1}{5} = 1$ $\frac{5}{8}x = 1 + \frac{1}{5}$ $\frac{5}{8}x = \frac{6}{5}$ $x = \frac{6}{5} \cdot \frac{8}{5}$ $x = \frac{48}{25} = 1\frac{23}{25}$ м) $\frac{3}{5}z + \frac{2}{3}z - 3 = \frac{4}{5}$ $\frac{9}{15}z + \frac{10}{15}z = \frac{4}{5} + 3$ $\frac{19}{15}z = \frac{19}{5}$ $z = \frac{19}{5} \cdot \frac{15}{19}$ $z = 3$