Вычислите: 2 4/15 - (2 - 1 1/15) : 4/9 + 2/3

Привет! Давай решим эти примеры по порядку. Везде будем соблюдать приоритет действий: сначала скобки, потом деление, затем сложение и вычитание. 1. $2\frac{4}{15} - (2 - 1\frac{1}{15}) : \frac{4}{9} + \frac{2}{3} = 2\frac{4}{15} - (\frac{14}{15}) : \frac{4}{9} + \frac{2}{3} = \frac{34}{15} - (\frac{14}{15} \cdot \frac{9}{4}) + \frac{2}{3} = \frac{34}{15} - \frac{21}{10} + \frac{2}{3} = \frac{68}{30} - \frac{63}{30} + \frac{20}{30} = \frac{25}{30} = \frac{5}{6}$ 2. $1\frac{13}{14} - (2 - 1\frac{11}{35}) : \frac{9}{25} + \frac{4}{21} = \frac{27}{14} - (\frac{24}{35}) : \frac{9}{25} + \frac{4}{21} = \frac{27}{14} - (\frac{24}{35} \cdot \frac{25}{9}) + \frac{4}{21} = \frac{27}{14} - \frac{40}{21} + \frac{4}{21} = \frac{27}{14} - \frac{36}{21} = \frac{27}{14} - \frac{12}{7} = \frac{3}{14}$ 3. $3\frac{9}{10} - (2 - 1\frac{11}{35}) : \frac{9}{49} + \frac{1}{2} = \frac{39}{10} - (\frac{24}{35}) : \frac{9}{49} + \frac{1}{2} = \frac{39}{10} - (\frac{24}{35} \cdot \frac{49}{9}) + \frac{1}{2} = \frac{39}{10} - \frac{56}{15} + \frac{1}{2} = \frac{117}{30} - \frac{112}{30} + \frac{15}{30} = \frac{20}{30} = \frac{2}{3}$ 4. $\frac{9}{10} + \frac{4}{9} : (2 - 1\frac{11}{21}) - 1\frac{2}{3} = \frac{9}{10} + \frac{4}{9} : (\frac{10}{21}) - \frac{5}{3} = \frac{9}{10} + (\frac{4}{9} \cdot \frac{21}{10}) - \frac{5}{3} = \frac{9}{10} + \frac{14}{15} - \frac{5}{3} = \frac{27}{30} + \frac{28}{30} - \frac{50}{30} = \frac{5}{30} = \frac{1}{6}$ 5. $\frac{9}{22} - \frac{4}{9} : (3 - 1\frac{8}{15}) + \frac{8}{11} = \frac{9}{22} - \frac{4}{9} : (\frac{22}{15}) + \frac{8}{11} = \frac{9}{22} - (\frac{4}{9} \cdot \frac{15}{22}) + \frac{8}{11} = \frac{9}{22} - \frac{10}{33} + \frac{8}{11} = \frac{27}{66} - \frac{20}{66} + \frac{48}{66} = \frac{55}{66} = \frac{5}{6}$ 6. $\frac{7}{10} - \frac{9}{49} : (3 - 1\frac{13}{14}) + \frac{2}{5} = \frac{7}{10} - \frac{9}{49} : (\frac{15}{14}) + \frac{2}{5} = \frac{7}{10} - (\frac{9}{49} \cdot \frac{14}{15}) + \frac{2}{5} = \frac{7}{10} - \frac{6}{35} + \frac{2}{5} = \frac{49}{70} - \frac{12}{70} + \frac{28}{70} = \frac{65}{70} = \frac{13}{14}$ 7. $\frac{3}{10} - \frac{9}{25} : (4 - 1\frac{9}{10}) + \frac{4}{7} = \frac{3}{10} - \frac{9}{25} : (\frac{21}{10}) + \frac{4}{7} = \frac{3}{10} - (\frac{9}{25} \cdot \frac{10}{21}) + \frac{4}{7} = \frac{3}{10} - \frac{6}{35} + \frac{4}{7} = \frac{21}{70} - \frac{12}{70} + \frac{40}{70} = \frac{49}{70} = \frac{7}{10}$ 8. $\frac{5}{6} - \frac{25}{49} : (3 - 1\frac{13}{14}) + \frac{1}{2} = \frac{5}{6} - \frac{25}{49} : (\frac{15}{14}) + \frac{1}{2} = \frac{5}{6} - (\frac{25}{49} \cdot \frac{14}{15}) + \frac{1}{2} = \frac{5}{6} - \frac{10}{21} + \frac{1}{2} = \frac{35}{42} - \frac{20}{42} + \frac{21}{42} = \frac{36}{42} = \frac{6}{7}$