Вычисли значения выражений с дробями: 1/8 + 3/8

Конечно, сейчас помогу всё решить! 1) $\frac{1}{8} + \frac{3}{8} = \frac{1+3}{8} = \frac{4}{8} = \frac{1}{2}$ 2) $3 + \frac{2}{9} = \frac{3 \cdot 9}{9} + \frac{2}{9} = \frac{27}{9} + \frac{2}{9} = \frac{27+2}{9} = \frac{29}{9} = 3\frac{2}{9}$ 3) $\frac{7}{10} - \frac{3}{10} = \frac{7-3}{10} = \frac{4}{10} = \frac{2}{5}$ 4) $4\frac{3}{8} - \frac{1}{5} = \frac{4 \cdot 8 + 3}{8} - \frac{1}{5} = \frac{35}{8} - \frac{1}{5} = \frac{35 \cdot 5}{8 \cdot 5} - \frac{1 \cdot 8}{5 \cdot 8} = \frac{175}{40} - \frac{8}{40} = \frac{175-8}{40} = \frac{167}{40} = 4\frac{7}{40}$ 5) $\frac{7}{9} + \frac{2}{15} = \frac{7 \cdot 5}{9 \cdot 5} + \frac{2 \cdot 3}{15 \cdot 3} = \frac{35}{45} + \frac{6}{45} = \frac{35+6}{45} = \frac{41}{45}$ 6) $3\frac{1}{6} + \frac{2}{19} = \frac{3 \cdot 6 + 1}{6} + \frac{2}{19} = \frac{19}{6} + \frac{2}{19} = \frac{19 \cdot 19}{6 \cdot 19} + \frac{2 \cdot 6}{19 \cdot 6} = \frac{361}{114} + \frac{12}{114} = \frac{361+12}{114} = \frac{373}{114} = 3\frac{31}{114}$ 7) $3 - \frac{4}{111} = \frac{3 \cdot 111}{111} - \frac{4}{111} = \frac{333}{111} - \frac{4}{111} = \frac{333-4}{111} = \frac{329}{111} = 2\frac{107}{111}$ 8) $7\frac{1}{16} - 3\frac{5}{24} = \frac{7 \cdot 16 + 1}{16} - \frac{3 \cdot 24 + 5}{24} = \frac{113}{16} - \frac{77}{24} = \frac{113 \cdot 3}{16 \cdot 3} - \frac{77 \cdot 2}{24 \cdot 2} = \frac{339}{48} - \frac{154}{48} = \frac{339-154}{48} = \frac{185}{48} = 3\frac{41}{48}$