а) 3 3/7 * 3 1/2 : (1 1/11 - 27/55); б) (2 1/2 : 10 + 10 : 2 1/2 - 2 1/6) * 36/125; в) 3 1/8 : ((4 5/12 - 3 13/24) * 4/7 + (3 1/18 - 2 7/12) * 1 10/17).

Решение номера 1116: **а)** $3\frac{3}{7} \cdot 3\frac{1}{2} : (1\frac{1}{11} - \frac{27}{55})$ 1. $1\frac{1}{11} - \frac{27}{55} = \frac{12}{11} - \frac{27}{55} = \frac{60}{55} - \frac{27}{55} = \frac{33}{55} = \frac{3}{5}$ 2. $3\frac{3}{7} \cdot 3\frac{1}{2} = \frac{24}{7} \cdot \frac{7}{2} = \frac{12}{1} = 12$ 3. $12 : \frac{3}{5} = 12 \cdot \frac{5}{3} = 4 \cdot 5 = 20$ **Ответ: 20** **б)** $(2\frac{1}{2} : 10 + 10 : 2\frac{1}{2} - 2\frac{1}{6}) \cdot \frac{36}{125}$ 1. $2\frac{1}{2} : 10 = \frac{5}{2} : 10 = \frac{5}{2} \cdot \frac{1}{10} = \frac{1}{4}$ 2. $10 : 2\frac{1}{2} = 10 : \frac{5}{2} = 10 \cdot \frac{2}{5} = 4$ 3. $\frac{1}{4} + 4 = 4\frac{1}{4} = \frac{17}{4}$ 4. $\frac{17}{4} - 2\frac{1}{6} = \frac{51}{12} - \frac{26}{12} = \frac{25}{12}$ 5. $\frac{25}{12} \cdot \frac{36}{125} = \frac{1}{1} \cdot \frac{3}{5} = \frac{3}{5} = 0{,}6$ **Ответ: 0{,}6** **в)** $3\frac{1}{8} : ((4\frac{5}{12} - 3\frac{13}{24}) \cdot \frac{4}{7} + (3\frac{1}{18} - 2\frac{7}{12}) \cdot 1\frac{10}{17})$ 1. $4\frac{5}{12} - 3\frac{13}{24} = 4\frac{10}{24} - 3\frac{13}{24} = 3\frac{34}{24} - 3\frac{13}{24} = \frac{21}{24} = \frac{7}{8}$ 2. $\frac{7}{8} \cdot \frac{4}{7} = \frac{1}{2}$ 3. $3\frac{1}{18} - 2\frac{7}{12} = 3\frac{2}{36} - 2\frac{21}{36} = 2\frac{38}{36} - 2\frac{21}{36} = \frac{17}{36}$ 4. $\frac{17}{36} \cdot 1\frac{10}{17} = \frac{17}{36} \cdot \frac{27}{17} = \frac{27}{36} = \frac{3}{4}$ 5. $\frac{1}{2} + \frac{3}{4} = \frac{2}{4} + \frac{3}{4} = \frac{5}{4}$ 6. $3\frac{1}{8} : \frac{5}{4} = \frac{25}{8} \cdot \frac{4}{5} = \frac{5}{2} = 2\frac{1}{2}$ **Ответ: 2{,}5**