Вычисли выражения a, б, в, г, д, е.

Решаю примеры по порядку. a) $$(4 \frac{3}{4} - 3 \frac{1}{12}) \cdot 4 = (\frac{19}{4} - \frac{37}{12}) \cdot 4 = (\frac{57}{12} - \frac{37}{12}) \cdot 4 = \frac{20}{12} \cdot 4 = \frac{5}{3} \cdot 4 = \frac{20}{3} = 6 \frac{2}{3}$$ б) $$(5 \frac{14}{19} - 5 \frac{1}{38}) \cdot 38 = (\frac{109}{19} - \frac{191}{38}) \cdot 38 = (\frac{218}{38} - \frac{191}{38}) \cdot 38 = \frac{27}{38} \cdot 38 = 27$$ в) $$7 \frac{4}{19} \cdot 6 \frac{1}{4} + 4 \frac{15}{19} \cdot 6 \frac{1}{4} = 6 \frac{1}{4} \cdot (7 \frac{4}{19} + 4 \frac{15}{19}) = 6 \frac{1}{4} \cdot (11 \frac{19}{19}) = 6 \frac{1}{4} \cdot 12 = \frac{25}{4} \cdot 12 = 25 \cdot 3 = 75$$ г) $$3 \frac{1}{14} \cdot 17 \frac{7}{29} - 3 \frac{1}{14} \cdot 3 \frac{7}{29} = 3 \frac{1}{14} \cdot (17 \frac{7}{29} - 3 \frac{7}{29}) = 3 \frac{1}{14} \cdot 14 = \frac{43}{14} \cdot 14 = 43$$ д) $$(1 \frac{1}{2} + 2 \frac{1}{16}) \cdot 2 \frac{10}{11} : (2 \frac{1}{16} - 1 \frac{7}{8}) = (\frac{3}{2} + \frac{33}{16}) \cdot \frac{32}{11} : (\frac{33}{16} - \frac{15}{8}) = (\frac{24}{16} + \frac{33}{16}) \cdot \frac{32}{11} : (\frac{33}{16} - \frac{30}{16}) = \frac{57}{16} \cdot \frac{32}{11} : \frac{3}{16} = \frac{57}{1} \cdot \frac{2}{11} : \frac{3}{16} = \frac{114}{11} \cdot \frac{16}{3} = \frac{114 \cdot 16}{11 \cdot 3} = \frac{38 \cdot 16}{11} = \frac{608}{11} = 55 \frac{3}{11}$$ е) $$2 \frac{2}{3} : (2 \frac{1}{16} - 1 \frac{7}{8}) = \frac{8}{3} : (\frac{33}{16} - \frac{15}{8}) = \frac{8}{3} : (\frac{33}{16} - \frac{30}{16}) = \frac{8}{3} : \frac{3}{16} = \frac{8}{3} \cdot \frac{16}{3} = \frac{8 \cdot 16}{3 \cdot 3} = \frac{128}{9} = 14 \frac{2}{9}$$ **Ответы:** а) $6 \frac{2}{3}$ б) 27 в) 75 г) 43 д) $55 \frac{3}{11}$ е) $14 \frac{2}{9}$