Вопрос:

Найди значение выражения в заданиях 3-6.

Фотография

Ответ ассистента

Конечно, сейчас помогу! **Задание 3** 1) $10 \cdot (\frac{1}{5})^2 - 12 \cdot \frac{1}{5} = 10 \cdot \frac{1}{25} - \frac{12}{5} = \frac{10}{25} - \frac{60}{25} = -\frac{50}{25} = -2$ 2) $8 \cdot (\frac{1}{4})^2 - 14 \cdot \frac{1}{4} = 8 \cdot \frac{1}{16} - \frac{14}{4} = \frac{8}{16} - \frac{56}{16} = -\frac{48}{16} = -3$ 3) $21 \cdot (\frac{1}{7})^2 - 10 \cdot \frac{1}{7} = 21 \cdot \frac{1}{49} - \frac{10}{7} = \frac{21}{49} - \frac{70}{49} = -\frac{49}{49} = -1$ 4) $6 \cdot (\frac{1}{3})^2 - 17 \cdot \frac{1}{3} = 6 \cdot \frac{1}{9} - \frac{17}{3} = \frac{6}{9} - \frac{51}{9} = -\frac{45}{9} = -5$ 5) $18 \cdot (\frac{1}{9})^2 - 20 \cdot \frac{1}{9} = 18 \cdot \frac{1}{81} - \frac{20}{9} = \frac{18}{81} - \frac{180}{81} = -\frac{162}{81} = -2$ 6) $15 \cdot (\frac{1}{5})^2 - 8 \cdot \frac{1}{5} = 15 \cdot \frac{1}{25} - \frac{8}{5} = \frac{15}{25} - \frac{40}{25} = -\frac{25}{25} = -1$ **Задание 4** 1) $\frac{2.1}{6.6 - 2.4} = \frac{2.1}{4.2} = 0.5$ 2) $\frac{7.2}{8.3 - 8.6} = \frac{7.2}{-0.3} = -24$ 3) $\frac{9.2}{0.5 - 2.8} = \frac{9.2}{-2.3} = -4$ 4) $\frac{1.6}{2.5 + 0.7} = \frac{1.6}{3.2} = 0.5$ 5) $\frac{5.6}{1.9 + 2.1} = \frac{5.6}{4} = 1.4$ 6) $\frac{9.4}{4.1 + 5.3} = \frac{9.4}{9.4} = 1$ 7) $\frac{9.5 + 8.9}{2.3} = \frac{18.4}{2.3} = 8$ 8) $\frac{6.8 - 4.7}{1.4} = \frac{2.1}{1.4} = 1.5$ 9) $\frac{7.5 + 3.5}{2.5} = \frac{11}{2.5} = 4.4$ 10) $\frac{6.9 - 4.1}{0.2} = \frac{2.8}{0.2} = 14$ 11) $\frac{1.7 + 3.8}{2.2} = \frac{5.5}{2.2} = 2.5$ 12) $\frac{7.2 - 6.1}{2.2} = \frac{1.1}{2.2} = 0.5$ 13) $\frac{27}{3 \cdot 4.5} = \frac{27}{13.5} = 2$ 14) $\frac{16}{3.2 \cdot 2} = \frac{16}{6.4} = 2.5$ 15) $\frac{36}{4.4 + 4.5} = \frac{36}{8.9} = 4.04494382$ 16) $\frac{21}{17.5 - 0.8} = \frac{21}{16.7} = 1.25748503$ 17) $\frac{22}{4.4 \cdot 2.5} = \frac{22}{11} = 2$ 18) $\frac{7}{12.5 \cdot 1.4} = \frac{7}{17.5} = 0.4$ 19) $\frac{8.4 \cdot 1.3}{0.7} = \frac{10.92}{0.7} = 15.6$ 20) $\frac{4.4 - 0.3}{6.6} = \frac{4.1}{6.6} = 0.62121212$ 21) $\frac{4.8 \cdot 0.4}{0.6} = \frac{1.92}{0.6} = 3.2$ 22) $\frac{8.8 \cdot 0.8}{4.4} = \frac{7.04}{4.4} = 1.6$ 23) $\frac{0.3 \cdot 7.5}{0.5} = \frac{2.25}{0.5} = 4.5$ 24) $\frac{5.6 \cdot 0.3}{0.8} = \frac{1.68}{0.8} = 2.1$ **Задание 5** 1) $\frac{0.9}{1 + \frac{1}{5}} = \frac{0.9}{\frac{6}{5}} = 0.9 \cdot \frac{5}{6} = \frac{4.5}{6} = 0.75$ 2) $\frac{2.6}{1 - \frac{1}{14}} = \frac{2.6}{\frac{13}{14}} = 2.6 \cdot \frac{14}{13} = \frac{36.4}{13} = 2.8$ 3) $\frac{1.3}{1 + \frac{1}{12}} = \frac{1.3}{\frac{13}{12}} = 1.3 \cdot \frac{12}{13} = \frac{15.6}{13} = 1.2$ 4) $\frac{1.2}{1 - \frac{1}{3}} = \frac{1.2}{\frac{2}{3}} = 1.2 \cdot \frac{3}{2} = \frac{3.6}{2} = 1.8$ 5) $\frac{0.6}{1 + \frac{1}{2}} = \frac{0.6}{\frac{3}{2}} = 0.6 \cdot \frac{2}{3} = \frac{1.2}{3} = 0.4$ 6) $\frac{0.8}{1 - \frac{1}{9}} = \frac{0.8}{\frac{8}{9}} = 0.8 \cdot \frac{9}{8} = \frac{7.2}{8} = 0.9$ **Задание 6** 1) $-7 \cdot (-4.7) - 6.8 = 32.9 - 6.8 = 26.1$ 2) $-13 \cdot (-9.3) - 7.8 = 120.9 - 7.8 = 113.1$ 3) $-12 \cdot (-8.6) - 9.4 = 103.2 - 9.4 = 93.8$ 4) $7.6 - 8 \cdot (-5.2) = 7.6 + 41.6 = 49.2$ 5) $6.8 - 11 \cdot (-6.1) = 6.8 + 67.1 = 73.9$ 6) $5.3 - 9 \cdot (-4.4) = 5.3 + 39.6 = 44.9$ 7) $-0.8 \cdot (-10)^2 - 95 = -0.8 \cdot 100 - 95 = -80 - 95 = -175$ 8) $0.7 \cdot (-10)^3 - 20 = 0.7 \cdot (-1000) - 20 = -700 - 20 = -720$ 9) $-0.2 \cdot (-10)^2 + 55 = -0.2 \cdot 100 + 55 = -20 + 55 = 35$ 10) $0.9 \cdot (-10)^3 + 50 = 0.9 \cdot (-1000) + 50 = -900 + 50 = -850$ 11) $-0.7 \cdot (-10)^2 - 120 = -0.7 \cdot 100 - 120 = -70 - 120 = -190$ 12) $0.6 \cdot (-10)^3 + 50 = 0.6 \cdot (-1000) + 50 = -600 + 50 = -550$ 13) $30 - 0.8 \cdot (-10)^2 = 30 - 0.8 \cdot 100 = 30 - 80 = -50$ 14) $80 + 0.4 \cdot (-10)^3 = 80 + 0.4 \cdot (-1000) = 80 - 400 = -320$ 15) $55 + 0.2 \cdot (-10)^2 = 55 + 0.2 \cdot 100 = 55 + 20 = 75$ 16) $-60 + 0.4 \cdot (-10)^2 = -60 + 0.4 \cdot 100 = -60 + 40 = -20$ 17) $-80 + 0.3 \cdot (-10)^3 = -80 + 0.3 \cdot (-1000) = -80 - 300 = -380$ 18) $-45 + 0.5 \cdot (-10)^2 = -45 + 0.5 \cdot 100 = -45 + 50 = 5$

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