Выполни действия с дробями: a) 6 1/3 - 8

- a) $6\frac{1}{3} - 8 = \frac{19}{3} - 8 = \frac{19 - 24}{3} = -\frac{5}{3} = -1\frac{2}{3}$ - б) $-2\frac{2}{7} + 4\frac{3}{5} = -\frac{16}{7} + \frac{23}{5} = \frac{-16 \cdot 5 + 23 \cdot 7}{35} = \frac{-80 + 161}{35} = \frac{81}{35} = 2\frac{11}{35}$ - г) $3\frac{8}{9} : (-\frac{16}{9}) = \frac{35}{9} : (-\frac{16}{9}) = \frac{35}{9} \cdot (-\frac{9}{16}) = -\frac{35}{16} = -2\frac{3}{16}$ - д) $5\frac{5}{12} \cdot (-6) = \frac{65}{12} \cdot (-6) = -\frac{65}{2} = -32\frac{1}{2}$ - e) $-3\frac{2}{9} \cdot 3 = -\frac{29}{9} \cdot 3 = -\frac{29}{3} = -9\frac{2}{3}$ - ж) $\frac{4}{7} : (-49) = \frac{4}{7} \cdot (-\frac{1}{49}) = -\frac{4}{343}$ - з) $-16 : (-\frac{4}{9}) = -16 \cdot (-\frac{9}{4}) = 4 \cdot 9 = 36$ - и) $-3\frac{1}{2} \cdot (-1\frac{1}{3}) = -\frac{7}{2} \cdot (-\frac{4}{3}) = \frac{7 \cdot 2}{3} = \frac{14}{3} = 4\frac{2}{3}$