Реши примеры с обыкновенными и десятичными дробями.

1. $\frac{2}{11} + \frac{9}{11} = \frac{2+9}{11} = \frac{11}{11} = 1$ 2. $\frac{12}{17} - \frac{5}{17} = \frac{12-5}{17} = \frac{7}{17}$ 3. $\frac{7}{15} + \frac{1}{15} + \frac{6}{15} = \frac{7+1+6}{15} = \frac{14}{15}$ 4. $\frac{13}{23} - \frac{4}{23} - \frac{1}{23} = \frac{13-4-1}{23} = \frac{8}{23}$ 5. $3\frac{7}{12} + 5\frac{1}{12} = (3+5) + (\frac{7}{12} + \frac{1}{12}) = 8 + \frac{8}{12} = 8\frac{2}{3}$ 6. $2\frac{1}{2} + 7 = 2 + \frac{1}{2} + 7 = 9\frac{1}{2}$ 7. $4\frac{1}{6} + 10 = 14\frac{1}{6}$ 8. $7\frac{5}{7} + 4\frac{2}{7} = (7+4) + (\frac{5}{7} + \frac{2}{7}) = 11 + \frac{7}{7} = 11+1 = 12$ 9. $4 - \frac{3}{7} = \frac{4*7}{7} - \frac{3}{7} = \frac{28-3}{7} = \frac{25}{7} = 3\frac{4}{7}$ 10. $5 - 3\frac{3}{5} = 5 - (3 + \frac{3}{5}) = 5 - 3 - \frac{3}{5} = 2 - \frac{3}{5} = \frac{2*5}{5} - \frac{3}{5} = \frac{10-3}{5} = \frac{7}{5} = 1\frac{2}{5}$ 11. $8\frac{9}{13} + \frac{5}{13} = 8 + \frac{9}{13} + \frac{5}{13} = 8 + \frac{14}{13} = 8 + 1\frac{1}{13} = 9\frac{1}{13}$ 12. $4\frac{3}{5} - 1\frac{4}{5} = 4\frac{3}{5} - 1\frac{4}{5} = 3\frac{8}{5} - 1\frac{4}{5} = (3-1) + (\frac{8}{5} - \frac{4}{5}) = 2 + \frac{4}{5} = 2\frac{4}{5}$ 13. $6\frac{14}{17} - 3\frac{2}{17} + 2\frac{5}{17} = (6-3+2) + (\frac{14}{17} - \frac{2}{17} + \frac{5}{17}) = 5 + \frac{17}{17} = 5 + 1 = 6$ 14. $8\frac{1}{5} + 2\frac{4}{5} - 3 = (8+2-3) + (\frac{1}{5} + \frac{4}{5}) = 7 + \frac{5}{5} = 7 + 1 = 8$ 15. $\frac{25}{33} + 5\frac{13}{33} - \frac{4}{33} = 5 + (\frac{25}{33} + \frac{13}{33} - \frac{4}{33}) = 5 + \frac{34}{33} = 5 + 1\frac{1}{33} = 6\frac{1}{33}$ 16. $9\frac{1}{6} + 3\frac{5}{18} = (9+3) + (\frac{1}{6} + \frac{5}{18}) = 12 + (\frac{1*3}{6*3} + \frac{5}{18}) = 12 + (\frac{3}{18} + \frac{5}{18}) = 12 + \frac{8}{18} = 12 + \frac{4}{9} = 12\frac{4}{9}$ 17. $9\frac{1}{6} - 3\frac{5}{18} = (9-3) + (\frac{1}{6} - \frac{5}{18}) = 6 + (\frac{1*3}{6*3} - \frac{5}{18}) = 6 + (\frac{3}{18} - \frac{5}{18}) = 6 - \frac{2}{18} = 6 - \frac{1}{9} = 5\frac{8}{9}$ 18. $10\frac{5}{8} - 2\frac{7}{16} = (10-2) + (\frac{5}{8} - \frac{7}{16}) = 8 + (\frac{5*2}{8*2} - \frac{7}{16}) = 8 + (\frac{10}{16} - \frac{7}{16}) = 8 + \frac{3}{16} = 8\frac{3}{16}$ 19. $5\frac{1}{8} + 14\frac{7}{12} = (5+14) + (\frac{1}{8} + \frac{7}{12}) = 19 + (\frac{1*3}{8*3} + \frac{7*2}{12*2}) = 19 + (\frac{3}{24} + \frac{14}{24}) = 19 + \frac{17}{24} = 19\frac{17}{24}$ 20. $8\frac{5}{9} + 3\frac{5}{6} = (8+3) + (\frac{5}{9} + \frac{5}{6}) = 11 + (\frac{5*2}{9*2} + \frac{5*3}{6*3}) = 11 + (\frac{10}{18} + \frac{15}{18}) = 11 + \frac{25}{18} = 11 + 1\frac{7}{18} = 12\frac{7}{18}$ 21. $5\frac{2}{3} - 3\frac{1}{5} = (5-3) + (\frac{2}{3} - \frac{1}{5}) = 2 + (\frac{2*5}{3*5} - \frac{1*3}{5*3}) = 2 + (\frac{10}{15} - \frac{3}{15}) = 2 + \frac{7}{15} = 2\frac{7}{15}$ 22. $12\frac{5}{12} - 8\frac{7}{18} = (12-8) + (\frac{5}{12} - \frac{7}{18}) = 4 + (\frac{5*3}{12*3} - \frac{7*2}{18*2}) = 4 + (\frac{15}{36} - \frac{14}{36}) = 4 + \frac{1}{36} = 4\frac{1}{36}$ 23. $3\frac{5}{16} - \frac{1}{4} - \frac{1}{16} = 3 + (\frac{5}{16} - \frac{1*4}{4*4} - \frac{1}{16}) = 3 + (\frac{5}{16} - \frac{4}{16} - \frac{1}{16}) = 3 + \frac{0}{16} = 3$ 24. $5\frac{11}{12} - 2\frac{1}{6} - 1\frac{1}{4} = (5-2-1) + (\frac{11}{12} - \frac{1*2}{6*2} - \frac{1*3}{4*3}) = 2 + (\frac{11}{12} - \frac{2}{12} - \frac{3}{12}) = 2 + \frac{6}{12} = 2 + \frac{1}{2} = 2\frac{1}{2}$ 25. $\frac{1}{8} + 1\frac{3}{5} + 2\frac{7}{8} = (1+2) + (\frac{1}{8} + \frac{3}{5} + \frac{7}{8}) = 3 + (\frac{1*5}{8*5} + \frac{3*8}{5*8} + \frac{7*5}{8*5}) = 3 + (\frac{5}{40} + \frac{24}{40} + \frac{35}{40}) = 3 + \frac{64}{40} = 3 + 1\frac{24}{40} = 4\frac{3}{5}$ 26. $2\frac{7}{9} - 1\frac{5}{18} + 5\frac{1}{2} = (2-1+5) + (\frac{7}{9} - \frac{5}{18} + \frac{1}{2}) = 6 + (\frac{7*2}{9*2} - \frac{5}{18} + \frac{1*9}{2*9}) = 6 + (\frac{14}{18} - \frac{5}{18} + \frac{9}{18}) = 6 + \frac{18}{18} = 6 + 1 = 7$ 27. $\frac{1}{3} * \frac{2}{5} = \frac{1*2}{3*5} = \frac{2}{15}$ 28. $\frac{1}{2} * \frac{4}{7} = \frac{1*4}{2*7} = \frac{4}{14} = \frac{2}{7}$ 29. $\frac{11}{12} - \frac{4}{22} = \frac{11}{12} - \frac{2}{11} = (\frac{11*11}{12*11} - \frac{2*12}{11*12}) = \frac{121}{132} - \frac{24}{132} = \frac{97}{132}$ 30. $\frac{17}{26} + \frac{13}{34} = \frac{17*17}{26*17} + \frac{13*13}{34*13} = \frac{289}{442} + \frac{169}{442} = \frac{458}{442} = \frac{229}{221} = 1\frac{8}{221}$