1). $(\frac{5}{14} + \frac{17}{42}) \cdot 1\frac{6}{8} = (\frac{15}{42} + \frac{17}{42}) \cdot \frac{14}{8} = \frac{32}{42} \cdot \frac{7}{4} = \frac{16}{21} \cdot \frac{7}{4} = \frac{4}{3} = 1\frac{1}{3}$
2). $(5\frac{8}{9} : 1\frac{17}{36} + 1\frac{1}{4}) \cdot \frac{5}{21} = (\frac{53}{9} : \frac{53}{36} + \frac{5}{4}) \cdot \frac{5}{21} = (4 + \frac{5}{4}) \cdot \frac{5}{21} = 5\frac{1}{4} \cdot \frac{5}{21} = \frac{21}{4} \cdot \frac{5}{21} = \frac{5}{4} = 1\frac{1}{4}$
3). $(2\frac{1}{4} + 4\frac{5}{6}) : 3\frac{2}{5} - \frac{3}{4} : \frac{3}{5} = (2\frac{3}{12} + 4\frac{10}{12}) : \frac{17}{5} - \frac{3}{4} \cdot \frac{5}{3} = 7\frac{1}{12} : \frac{17}{5} - \frac{5}{4} = \frac{85}{12} \cdot \frac{5}{17} - \frac{5}{4} = \frac{25}{12} - \frac{15}{12} = \frac{10}{12} = \frac{5}{6}$
4). $(3\frac{1}{4} + 3\frac{5}{6}) : (5\frac{3}{4} - 3\frac{2}{3}) = (3\frac{3}{12} + 3\frac{10}{12}) : (5\frac{9}{12} - 3\frac{8}{12}) = 6\frac{13}{12} : 2\frac{1}{12} = 7\frac{1}{12} : 2\frac{1}{12} = \frac{85}{12} : \frac{25}{12} = \frac{85}{25} = 3\frac{2}{5}$
5). $(6\frac{4}{5} - 2\frac{3}{4}) : (2\frac{16}{21} + 3\frac{2}{3}) = (6\frac{16}{20} - 2\frac{15}{20}) : (2\frac{16}{21} + 3\frac{14}{21}) = 4\frac{1}{20} : 5\frac{30}{21} = \frac{81}{20} : 6\frac{3}{7} = \frac{81}{20} : \frac{45}{7} = \frac{81}{20} \cdot \frac{7}{45} = \frac{9}{20} \cdot \frac{7}{5} = \frac{63}{100} = 0.63$
6). $(2\frac{3}{8} + 3\frac{7}{24}) : (4\frac{2}{3} - 1\frac{1}{8}) = (2\frac{9}{24} + 3\frac{7}{24}) : (4\frac{16}{24} - 1\frac{3}{24}) = 5\frac{16}{24} : 3\frac{13}{24} = 5\frac{2}{3} : 3\frac{13}{24} = \frac{17}{3} : \frac{85}{24} = \frac{17}{3} \cdot \frac{24}{85} = 1 \cdot \frac{8}{5} = 1\frac{3}{5}$
7). $(1\frac{3}{4} + 2\frac{1}{3}) : (7\frac{1}{2} - 1\frac{2}{3}) = (1\frac{9}{12} + 2\frac{4}{12}) : (7\frac{3}{6} - 1\frac{4}{6}) = 4\frac{1}{12} : (6\frac{9}{6} - 1\frac{4}{6}) = 4\frac{1}{12} : 5\frac{5}{6} = \frac{49}{12} : \frac{35}{6} = \frac{49}{12} \cdot \frac{6}{35} = \frac{7}{2} \cdot \frac{1}{5} = \frac{7}{10} = 0.7$
8). $(\frac{4}{5} + \frac{4}{7}) \cdot (3\frac{3}{8} + 2\frac{11}{4}) = (\frac{28}{35} + \frac{20}{35}) \cdot (3\frac{3}{8} + 4\frac{3}{4}) = \frac{48}{35} \cdot (3\frac{3}{8} + 4\frac{6}{8}) = \frac{48}{35} \cdot 8\frac{1}{8} = \frac{48}{35} \cdot \frac{65}{8} = \frac{6}{7} \cdot \frac{13}{1} = \frac{78}{7} = 11\frac{1}{7}$
9). $(3.6 - 1\frac{2}{3}) : (4\frac{1}{15} - 2\frac{7}{9}) = (3\frac{3}{5} - 1\frac{2}{3}) : (4\frac{3}{45} - 2\frac{35}{45}) = (3\frac{9}{15} - 1\frac{10}{15}) : (3\frac{48}{45} - 2\frac{35}{45}) = 1\frac{14}{15} : 1\frac{13}{45} = \frac{29}{15} : \frac{58}{45} = \frac{29}{15} \cdot \frac{45}{58} = 1 \cdot \frac{3}{2} = 1.5$
10). $4\frac{1}{6} \cdot (1\frac{1}{2} - \frac{3}{5}) + (\frac{3}{4} + \frac{5}{6}) \cdot 6 = \frac{25}{6} \cdot (1\frac{5}{10} - \frac{6}{10}) + (\frac{9}{12} + \frac{10}{12}) \cdot 6 = \frac{25}{6} \cdot \frac{9}{10} + \frac{19}{12} \cdot 6 = \frac{5}{2} \cdot \frac{3}{2} + \frac{19}{2} = \frac{15}{4} + \frac{38}{4} = \frac{53}{4} = 13\frac{1}{4}$
