2.Выполнить действия с обыкновенными дробями:

Допущение: Выполняю вычисления для всех примеров из задания 2. а) $1\frac{1}{5} + 1\frac{1}{3} = \frac{6}{5} + \frac{4}{3} = \frac{18+20}{15} = \frac{38}{15} = 2\frac{8}{15}$ б) $1\frac{1}{2} + 2\frac{3}{8} = \frac{3}{2} + \frac{19}{8} = \frac{12+19}{8} = \frac{31}{8} = 3\frac{7}{8}$ в) $\frac{3}{4} + 2 = 2\frac{3}{4}$ г) $\frac{2}{3} - \frac{1}{6} = \frac{4-1}{6} = \frac{3}{6} = \frac{1}{2}$ д) $\frac{7}{12} - 1 = \frac{7-12}{12} = -\frac{5}{12}$ е) $\frac{4}{5} - \frac{9}{10} = \frac{8-9}{10} = -\frac{1}{10}$ ё) $1\frac{1}{3} - 2 = -\frac{2}{3}$ ж) $1 + \frac{7}{3} = 1 + 2\frac{1}{3} = 3\frac{1}{3}$ з) $\frac{8}{15} : 4 = \frac{8}{15 \cdot 4} = \frac{2}{15}$ и) $3 : 2 = 1{,}5$ й) $-1 : \frac{3}{4} = -1 \cdot \frac{4}{3} = -\frac{4}{3} = -1\frac{1}{3}$ к) $\frac{7}{12} : (-\frac{1}{4}) = \frac{7}{12} \cdot (-4) = -\frac{7}{3} = -2\frac{1}{3}$ л) $\frac{1}{4} \cdot 2 = \frac{1}{2}$ м) $-\frac{3}{4} \cdot \frac{4}{9} = -\frac{3}{9} = -\frac{1}{3}$ н) $\frac{7}{9} \cdot \frac{18}{35} = \frac{1 \cdot 2}{1 \cdot 5} = \frac{2}{5}$ о) $\frac{4}{19} \cdot (-\frac{57}{64}) = -\frac{1 \cdot 3}{1 \cdot 16} = -\frac{3}{16}$ п) $2\frac{3}{4} + 3\frac{5}{7} = \frac{11}{4} + \frac{26}{7} = \frac{77+104}{28} = \frac{181}{28} = 6\frac{13}{28}$ р) $-4\frac{2}{3} + 7\frac{1}{2} = -\frac{14}{3} + \frac{15}{2} = \frac{-28+45}{6} = \frac{17}{6} = 2\frac{5}{6}$ с) $4\frac{1}{3} + \frac{1}{17} = \frac{13}{3} + \frac{1}{17} = \frac{221+3}{51} = \frac{224}{51} = 4\frac{20}{51}$ т) $-5\frac{2}{5} + 4\frac{1}{3} = -\frac{27}{5} + \frac{13}{3} = \frac{-81+65}{15} = -\frac{16}{15} = -1\frac{1}{15}$ у) $6\frac{1}{2} - 3\frac{3}{4} = \frac{13}{2} - \frac{15}{4} = \frac{26-15}{4} = \frac{11}{4} = 2\frac{3}{4}$ ф) $2\frac{1}{2} - 7\frac{5}{6} = \frac{5}{2} - \frac{47}{6} = \frac{15-47}{6} = -\frac{32}{6} = -5\frac{2}{6} = -5\frac{1}{3}$ х) $-4\frac{2}{3} - 7\frac{7}{9} = -\frac{14}{3} - \frac{70}{9} = \frac{-42-70}{9} = -\frac{112}{9} = -12\frac{4}{9}$ ц) $-2\frac{2}{3} - 3\frac{5}{9} = -\frac{8}{3} - \frac{32}{9} = \frac{-24-32}{9} = -\frac{56}{9} = -6\frac{2}{9}$ ч) $2\frac{3}{4} \cdot 5\frac{7}{33} = \frac{11}{4} \cdot \frac{172}{33} = \frac{1 \cdot 43}{1 \cdot 3} = \frac{43}{3} = 14\frac{1}{3}$ ш) $-3\frac{1}{2} \cdot 2\frac{2}{5} = -\frac{7}{2} \cdot \frac{12}{5} = -\frac{42}{5} = -8\frac{2}{5}$ щ) $-4\frac{5}{7} \cdot (-\frac{6}{11}) = \frac{33}{7} \cdot \frac{6}{11} = \frac{3 \cdot 6}{7 \cdot 1} = \frac{18}{7} = 2\frac{4}{7}$ ъ) $-3\frac{1}{2} \cdot 2\frac{2}{7} = -\frac{7}{2} \cdot \frac{16}{7} = -\frac{1}{1} \cdot \frac{8}{1} = -8$ ы) $4\frac{1}{3} : 2\frac{5}{6} = \frac{13}{3} : \frac{17}{6} = \frac{13}{3} \cdot \frac{6}{17} = \frac{13 \cdot 2}{17} = \frac{26}{17} = 1\frac{9}{17}$ ь) $-7\frac{3}{8} : (-2\frac{1}{16}) = -\frac{59}{8} : (-\frac{33}{16}) = \frac{59}{8} \cdot \frac{16}{33} = \frac{59 \cdot 2}{33} = \frac{118}{33} = 3\frac{19}{33}$ э) $-1\frac{1}{3} : 3\frac{1}{6} = -\frac{4}{3} : \frac{19}{6} = -\frac{4}{3} \cdot \frac{6}{19} = -\frac{4 \cdot 2}{19} = -\frac{8}{19}$ ю) $4\frac{1}{5} : 7\frac{1}{25} = \frac{21}{5} : \frac{176}{25} = \frac{21}{5} \cdot \frac{25}{176} = \frac{21 \cdot 5}{176} = \frac{105}{176}$