121. Найдите значение выражения 0,6·(-10)^4+5·(-10)^2-97.

Решим предложенные выражения: 121. $0,6 \cdot (-10)^4 + 5 \cdot (-10)^2 - 97 = 0,6 \cdot 10000 + 5 \cdot 100 - 97 = 6000 + 500 - 97 = 6403$ 122. $-0,8 \cdot (-10)^4 + 1 \cdot (-10)^2 - 51 = -0,8 \cdot 10000 + 100 - 51 = -8000 + 100 - 51 = -7951$ 123. $0,8 \cdot (-10)^4 + 3 \cdot (-10)^3 + 78 = 0,8 \cdot 10000 + 3 \cdot (-1000) + 78 = 8000 - 3000 + 78 = 5078$ 124. $14 \cdot (\frac{1}{2})^2 + 13 \cdot \frac{1}{2} = 14 \cdot \frac{1}{4} + 6,5 = 3,5 + 6,5 = 10$ 125. $6 \cdot (\frac{1}{3})^2 - 17 \cdot \frac{1}{3} = 6 \cdot \frac{1}{9} - \frac{17}{3} = \frac{2}{3} - \frac{17}{3} = -\frac{15}{3} = -5$ 126. $21 \cdot (\frac{1}{7})^2 - 10 \cdot \frac{1}{7} = 21 \cdot \frac{1}{49} - \frac{10}{7} = \frac{3}{7} - \frac{10}{7} = -\frac{7}{7} = -1$ 127. $33 \cdot (\frac{2}{11})^2 - 28 \cdot \frac{2}{11} = 33 \cdot \frac{4}{121} - \frac{56}{11} = \frac{3 \cdot 4}{11} - \frac{56}{11} = \frac{12}{11} - \frac{56}{11} = -\frac{44}{11} = -4$ 128. $(\frac{3}{4} - \frac{1}{6}) \cdot 3 = (\frac{9}{12} - \frac{2}{12}) \cdot 3 = \frac{7}{12} \cdot 3 = \frac{7}{4} = 1,75$ 129. $(\frac{2}{5} + \frac{13}{15}) \cdot 6 = (\frac{6}{15} + \frac{13}{15}) \cdot 6 = \frac{19}{15} \cdot 6 = \frac{19 \cdot 2}{5} = \frac{38}{5} = 7,6$ 130. $(\frac{9}{10} - \frac{7}{15}) \cdot 3 = (\frac{27}{30} - \frac{14}{30}) \cdot 3 = \frac{13}{30} \cdot 3 = \frac{13}{10} = 1,3$ 131. $(\frac{5}{6} + \frac{7}{15}) \cdot 3 = (\frac{25}{30} + \frac{14}{30}) \cdot 3 = \frac{39}{30} \cdot 3 = \frac{39}{10} = 3,9$