Д) $(5 \frac{7}{12} - 3 \frac{17}{36}) \cdot 2 \frac{1}{2} + 4 \frac{1}{3} \cdot \frac{3}{26} + \frac{1}{2}$

Д) $(5 \frac{7}{12} - 3 \frac{17}{36}) \cdot 2 \frac{1}{2} + 4 \frac{1}{3} \cdot \frac{3}{26} + \frac{1}{2} = (5 \frac{21}{36} - 3 \frac{17}{36}) \cdot \frac{5}{2} + \frac{13}{3} \cdot \frac{3}{26} + \frac{1}{2} = 2 \frac{4}{36} \cdot \frac{5}{2} + \frac{1}{2} + \frac{1}{2} = 2 \frac{1}{9} \cdot \frac{5}{2} + 1 = \frac{19}{9} \cdot \frac{5}{2} + 1 = \frac{95}{18} + 1 = 5 \frac{5}{18} + 1 = 6 \frac{5}{18}$ Е) $[(3 \frac{2}{5} + 1 \frac{7}{10}) \cdot 1 \frac{3}{17} - (2 \frac{7}{23} - 1 \frac{45}{46}) \cdot \frac{69}{80}] \cdot 1 \frac{1}{3} = [(3 \frac{4}{10} + 1 \frac{7}{10}) \cdot \frac{20}{17} - (2 \frac{14}{46} - 1 \frac{45}{46}) \cdot \frac{69}{80}] \cdot \frac{4}{3} = [5 \frac{1}{10} \cdot \frac{20}{17} - \frac{15}{46} \cdot \frac{69}{80}] \cdot \frac{4}{3} = [\frac{51}{10} \cdot \frac{20}{17} - \frac{9}{32}] \cdot \frac{4}{3} = [6 - \frac{9}{32}] \cdot \frac{4}{3} = 5 \frac{23}{32} \cdot \frac{4}{3} = \frac{183}{32} \cdot \frac{4}{3} = \frac{61}{8} = 7 \frac{5}{8}$ Ё) $8 \frac{2}{11} \cdot (4 \frac{3}{4} \cdot \frac{4}{57} + 7 \frac{2}{3} \cdot \frac{9}{46}) + 15 \cdot (5 \frac{7}{8} \cdot 3 \frac{3}{47} - 3 \frac{2}{3} \cdot \frac{31}{55}) = \frac{90}{11} \cdot (\frac{19}{4} \cdot \frac{4}{57} + \frac{23}{3} \cdot \frac{9}{46}) + 15 \cdot (\frac{47}{8} \cdot \frac{144}{47} - \frac{11}{3} \cdot \frac{31}{55}) = \frac{90}{11} \cdot (\frac{1}{3} + \frac{3}{2}) + 15 \cdot (18 - \frac{31}{15}) = \frac{90}{11} \cdot (\frac{2}{6} + \frac{9}{6}) + 15 \cdot (17 \frac{15}{15} - 2 \frac{1}{15}) = \frac{90}{11} \cdot \frac{11}{6} + 15 \cdot \frac{239}{15} = 15 + 239 = 254$ Ж) $\frac{3}{8} \cdot 5 + 4 \frac{1}{6} \cdot 2 \frac{1}{10} - \frac{9}{20} \cdot 6 = \frac{15}{8} + \frac{25}{6} \cdot \frac{21}{10} - \frac{54}{20} = 1 \frac{7}{8} + (\frac{5}{2} \cdot \frac{7}{2}) - 2 \frac{7}{10} = 1 \frac{7}{8} + 8 \frac{3}{4} - 2 \frac{7}{10} = 10 \frac{5}{8} - 2 \frac{7}{10} = 10 \frac{25}{40} - 2 \frac{28}{40} = 9 \frac{65}{40} - 2 \frac{28}{40} = 7 \frac{37}{40}$