Вычислите: 11) 1 46/49 * 2 11/12 * 4 8/19; 12) 6 13/21 - 1 4/7 * 1 2/3...

11. $1\frac{46}{49} \cdot 2\frac{11}{12} \cdot 4\frac{8}{19} = \frac{95}{49} \cdot \frac{35}{12} \cdot \frac{84}{19} = \frac{95 \cdot 35 \cdot 84}{49 \cdot 12 \cdot 19} = \frac{5 \cdot 5 \cdot 1}{1 \cdot 1 \cdot 1} \cdot \frac{1}{1} \cdot \frac{84}{12} = 25 \cdot 1 = 25$ 12. $6\frac{13}{21} - 1\frac{4}{7} \cdot 1\frac{2}{3} = 6\frac{13}{21} - \frac{11}{7} \cdot \frac{5}{3} = 6\frac{13}{21} - \frac{55}{21} = 6\frac{13}{21} - 2\frac{13}{21} = 4$ 13. $8\frac{11}{15} + 3\frac{25}{43} \cdot 2\frac{13}{15} = 8\frac{11}{15} + \frac{154}{43} \cdot \frac{43}{15} = 8\frac{11}{15} + \frac{154}{15} = 8\frac{11}{15} + 10\frac{4}{15} = 18\frac{15}{15} = 19$ 14. $1\frac{2}{7} \cdot 2\frac{1}{2} + 2\frac{3}{4} \cdot \frac{2}{7} = \frac{9}{7} \cdot \frac{5}{2} + \frac{11}{4} \cdot \frac{2}{7} = \frac{45}{14} + \frac{11}{14} = \frac{56}{14} = 4$ 15. $8\frac{1}{4} \cdot 1\frac{5}{18} + 5\frac{5}{8} \cdot \frac{7}{27} = \frac{33}{4} \cdot \frac{23}{18} + \frac{45}{8} \cdot \frac{7}{27} = \frac{11 \cdot 23}{4 \cdot 6} + \frac{5 \cdot 7}{8 \cdot 3} = \frac{253}{24} + \frac{35}{24} = \frac{288}{24} = 12$ 16. $\frac{5}{6} \cdot \frac{1}{2} \cdot \frac{12}{13} \cdot \frac{3}{10} = \frac{5 \cdot 1 \cdot 12 \cdot 3}{6 \cdot 2 \cdot 13 \cdot 10} = \frac{180}{1560} = \frac{18}{156} = \frac{3}{26}$ 17. $1\frac{1}{44} \cdot 2\frac{4}{9} \cdot \frac{1}{4} \cdot 9\frac{3}{5} = \frac{45}{44} \cdot \frac{22}{9} \cdot \frac{1}{4} \cdot \frac{48}{5} = \frac{45 \cdot 22 \cdot 1 \cdot 48}{44 \cdot 9 \cdot 4 \cdot 5} = \frac{5 \cdot 1 \cdot 1 \cdot 12}{2 \cdot 1 \cdot 1 \cdot 5} = \frac{60}{10} = 6$ 18. $6\frac{1}{3} \cdot 3\frac{3}{8} + (2\frac{1}{2})^3 = \frac{19}{3} \cdot \frac{27}{8} + (\frac{5}{2})^3 = \frac{19 \cdot 9}{8} + \frac{125}{8} = \frac{171}{8} + \frac{125}{8} = \frac{296}{8} = 37$ 19. $(4\frac{1}{3} + 1\frac{1}{6})^2 \cdot \frac{4}{11} = (4\frac{2}{6} + 1\frac{1}{6})^2 \cdot \frac{4}{11} = (5\frac{3}{6})^2 \cdot \frac{4}{11} = (5\frac{1}{2})^2 \cdot \frac{4}{11} = (\frac{11}{2})^2 \cdot \frac{4}{11} = \frac{121}{4} \cdot \frac{4}{11} = 11$ 20. ($\frac{5}{6} + \frac{2}{3})^3 \cdot 4\frac{4}{9} = (\frac{5}{6} + \frac{4}{6})^3 \cdot \frac{40}{9} = (\frac{9}{6})^3 \cdot \frac{40}{9} = (\frac{3}{2})^3 \cdot \frac{40}{9} = \frac{27}{8} \cdot \frac{40}{9} = \frac{3 \cdot 5}{1 \cdot 1} = 15$