Вычисли значения выражений a, б, в, г, д, е.

Привет! Давай помогу тебе с этими заданиями на вычисление значений выражений. a) $$\frac{4}{5} : 1\frac{1}{3} + 2\frac{1}{3} - 1 : 1\frac{3}{7} = $$ $$= \frac{4}{5} : \frac{4}{3} + \frac{7}{3} - 1 : \frac{10}{7} = $$ $$= \frac{4}{5} \cdot \frac{3}{4} + \frac{7}{3} - 1 \cdot \frac{7}{10} = $$ $$= \frac{3}{5} + \frac{7}{3} - \frac{7}{10} = $$ $$= \frac{18}{30} + \frac{70}{30} - \frac{21}{30} = $$ $$= \frac{18 + 70 - 21}{30} = \frac{67}{30} = 2\frac{7}{30}$$ б) $$2\frac{1}{6} : (\frac{1}{15} - \frac{1}{5}) + (2\frac{1}{8} + 3) : 5\frac{3}{4} = $$ $$= \frac{13}{6} : (\frac{1}{15} - \frac{3}{15}) + (\frac{17}{8} + \frac{24}{8}) : \frac{23}{4} = $$ $$= \frac{13}{6} : (-\frac{2}{15}) + \frac{41}{8} : \frac{23}{4} = $$ $$= \frac{13}{6} \cdot (-\frac{15}{2}) + \frac{41}{8} \cdot \frac{4}{23} = $$ $$= -\frac{13 \cdot 5}{2 \cdot 2} + \frac{41}{2 \cdot 23} = $$ $$= -\frac{65}{4} + \frac{41}{46} = $$ $$= \frac{-65 \cdot 23 + 41 \cdot 2}{92} = \frac{-1495 + 82}{92} = \frac{-1413}{92} = -15\frac{33}{92}$$ в) $$(1\frac{1}{4} + \frac{11}{14}) \cdot \frac{14}{57} - 2 : 1\frac{1}{6} \cdot \frac{7}{32} = $$ $$= (\frac{5}{4} + \frac{11}{14}) \cdot \frac{14}{57} - 2 : \frac{7}{6} \cdot \frac{7}{32} = $$ $$= (\frac{35}{28} + \frac{22}{28}) \cdot \frac{14}{57} - 2 \cdot \frac{6}{7} \cdot \frac{7}{32} = $$ $$= \frac{57}{28} \cdot \frac{14}{57} - \frac{2 \cdot 6 \cdot 7}{7 \cdot 32} = $$ $$= \frac{1}{2} - \frac{3}{8} = \frac{4}{8} - \frac{3}{8} = \frac{1}{8}$$ г) $$(2\frac{1}{2} + 3\frac{1}{3}) : 2\frac{1}{3} \cdot 9\frac{3}{5} = $$ $$= (\frac{5}{2} + \frac{10}{3}) : \frac{7}{3} \cdot \frac{48}{5} = $$ $$= (\frac{15}{6} + \frac{20}{6}) : \frac{7}{3} \cdot \frac{48}{5} = $$ $$= \frac{35}{6} : \frac{7}{3} \cdot \frac{48}{5} = $$ $$= \frac{35}{6} \cdot \frac{3}{7} \cdot \frac{48}{5} = $$ $$= \frac{5 \cdot 1 \cdot 48}{2 \cdot 1 \cdot 5} = \frac{48}{2} = 24$$ д) $$(10\frac{5}{13} - 7\frac{23}{26}) : \frac{5}{6} = $$ $$= (\frac{135}{13} - \frac{205}{26}) : \frac{5}{6} = $$ $$= (\frac{270}{26} - \frac{205}{26}) : \frac{5}{6} = $$ $$= \frac{65}{26} : \frac{5}{6} = $$ $$= \frac{5}{2} \cdot \frac{6}{5} = 3$$ е) $$(1\frac{1}{2})^3 : (3\frac{7}{8} - 2\frac{3}{4}) = $$ $$= (\frac{3}{2})^3 : (\frac{31}{8} - \frac{11}{4}) = $$ $$= \frac{27}{8} : (\frac{31}{8} - \frac{22}{8}) = $$ $$= \frac{27}{8} : \frac{9}{8} = $$ $$= \frac{27}{8} \cdot \frac{8}{9} = 3$$