Найди значение выражения, предварительно выполнив сокращение.

Задание 271. 1) $1\frac{1}{4} + 3\frac{5}{5} = 1\frac{1}{4} + 4 = 5\frac{1}{4}$ 2) $9\frac{2}{11} - 6\frac{5}{11} = 8\frac{13}{11} - 6\frac{5}{11} = 2\frac{8}{11}$ 3) $13\frac{9}{16} - 6\frac{32}{32} = 13\frac{9}{16} - 7 = 6\frac{9}{16}$ 4) $3\frac{5}{28} + 14\frac{7}{14} = 3\frac{5}{28} + 14\frac{1}{2} = 3\frac{5}{28} + 14\frac{14}{28} = 17\frac{19}{28}$ 5) $14\frac{7}{15} - 10\frac{7}{10} = 14\frac{14}{30} - 10\frac{21}{30} = 13\frac{44}{30} - 10\frac{21}{30} = 3\frac{23}{30}$ 6) $8\frac{3}{6} + 1\frac{1}{6} = 9\frac{4}{6} = 9\frac{2}{3}$ 7) $9\frac{7}{25} - 7\frac{17}{20} = 9\frac{28}{100} - 7\frac{85}{100} = 8\frac{128}{100} - 7\frac{85}{100} = 1\frac{43}{100}$ 8) $37\frac{17}{42} - 17\frac{17}{24} = 37\frac{68}{168} - 17\frac{119}{168} = 36\frac{236}{168} - 17\frac{119}{168} = 19\frac{117}{168} = 19\frac{39}{56}$ 9) $11\frac{3}{24} - 3\frac{11}{16} = 11\frac{6}{48} - 3\frac{33}{48} = 10\frac{54}{48} - 3\frac{33}{48} = 7\frac{21}{48} = 7\frac{7}{16}$ 10) $9\frac{7}{16} + 8\frac{9}{24} = 9\frac{21}{48} + 8\frac{18}{48} = 17\frac{39}{48} = 17\frac{13}{16}$ 11) $1\frac{1}{3} - 1\frac{1}{6} + 4\frac{1}{4} = 1\frac{2}{6} - 1\frac{1}{6} + 4\frac{1}{4} = \frac{1}{6} + 4\frac{1}{4} = \frac{2}{12} + 4\frac{3}{12} = 4\frac{5}{12}$ 12) $2\frac{4}{5} + 5\frac{2}{15} = 2\frac{12}{15} + 5\frac{2}{15} = 7\frac{14}{15}$