Реши примеры с дробями

Конечно, я помогу тебе решить эти примеры с дробями! **Столбик А** а) $\frac{3}{4} - \frac{2}{5} = \frac{3 \cdot 5 - 2 \cdot 4}{4 \cdot 5} = \frac{15 - 8}{20} = \frac{7}{20}$ б) $\frac{1}{3} + \frac{5}{12} = \frac{1 \cdot 4 + 5}{12} = \frac{4 + 5}{12} = \frac{9}{12} = \frac{3}{4}$ в) $\frac{5}{8} - \frac{3}{16} = \frac{5 \cdot 2 - 3}{16} = \frac{10 - 3}{16} = \frac{7}{16}$ г) $\frac{1}{10} + \frac{7}{10} = \frac{1 + 7}{10} = \frac{8}{10} = \frac{4}{5}$ д) $\frac{9}{17} + \frac{8}{17} = \frac{9 + 8}{17} = \frac{17}{17} = 1$ е) $\frac{2}{5} - \frac{1}{3} = \frac{2 \cdot 3 - 1 \cdot 5}{5 \cdot 3} = \frac{6 - 5}{15} = \frac{1}{15}$ ж) $\frac{1}{6} + \frac{5}{12} = \frac{1 \cdot 2 + 5}{12} = \frac{2 + 5}{12} = \frac{7}{12}$ з) $\frac{5}{9} - \frac{4}{27} = \frac{5 \cdot 3 - 4}{27} = \frac{15 - 4}{27} = \frac{11}{27}$ и) $\frac{1}{8} + \frac{3}{8} = \frac{1 + 3}{8} = \frac{4}{8} = \frac{1}{2}$ к) $\frac{7}{10} - \frac{1}{2} = \frac{7 - 1 \cdot 5}{10} = \frac{7 - 5}{10} = \frac{2}{10} = \frac{1}{5}$ **Столбик Б** а) $\frac{2}{7} + \frac{1}{6} = \frac{2 \cdot 6 + 1 \cdot 7}{7 \cdot 6} = \frac{12 + 7}{42} = \frac{19}{42}$ б) $\frac{7}{15} - \frac{1}{15} = \frac{7 - 1}{15} = \frac{6}{15} = \frac{2}{5}$ в) $\frac{2}{9} + \frac{7}{18} = \frac{2 \cdot 2 + 7}{18} = \frac{4 + 7}{18} = \frac{11}{18}$ г) $\frac{14}{21} - \frac{4}{7} = \frac{14 - 4 \cdot 3}{21} = \frac{14 - 12}{21} = \frac{2}{21}$ д) $\frac{4}{15} + \frac{1}{3} = \frac{4 + 1 \cdot 5}{15} = \frac{4 + 5}{15} = \frac{9}{15} = \frac{3}{5}$ е) $\frac{2}{3} - \frac{1}{9} = \frac{2 \cdot 3 - 1}{9} = \frac{6 - 1}{9} = \frac{5}{9}$ ж) $\frac{4}{5} + \frac{6}{25} = \frac{4 \cdot 5 + 6}{25} = \frac{20 + 6}{25} = \frac{26}{25} = 1 \frac{1}{25}$ з) $\frac{11}{12} - \frac{1}{12} = \frac{11 - 1}{12} = \frac{10}{12} = \frac{5}{6}$ и) $\frac{1}{2} + \frac{2}{7} = \frac{1 \cdot 7 + 2 \cdot 2}{2 \cdot 7} = \frac{7 + 4}{14} = \frac{11}{14}$ к) $\frac{13}{15} - \frac{2}{3} = \frac{13 - 2 \cdot 5}{15} = \frac{13 - 10}{15} = \frac{3}{15} = \frac{1}{5}$