Ты просишь меня решить примеры на вычитание смешанных чисел.

Конечно, давай решим эти примеры вместе! 1) $4\frac{14}{25} - 4\frac{11}{25} = \frac{4 \cdot 25 + 14}{25} - \frac{4 \cdot 25 + 11}{25} = \frac{114}{25} - \frac{111}{25} = \frac{3}{25}$$ 2) $12\frac{9}{14} - 4\frac{5}{14} = \frac{12 \cdot 14 + 9}{14} - \frac{4 \cdot 14 + 5}{14} = \frac{177}{14} - \frac{61}{14} = \frac{116}{14} = \frac{58}{7} = 8\frac{2}{7}$$ 3) $34\frac{6}{21} - 21\frac{5}{21} = \frac{34 \cdot 21 + 6}{21} - \frac{21 \cdot 21 + 5}{21} = \frac{720}{21} - \frac{446}{21} = \frac{274}{21} = 13\frac{1}{21}$$ 4) $5\frac{1}{3} - 2\frac{1}{3} = \frac{5 \cdot 3 + 1}{3} - \frac{2 \cdot 3 + 1}{3} = \frac{16}{3} - \frac{7}{3} = \frac{9}{3} = 3$ 5) $23\frac{13}{20} - 4\frac{1}{20} = \frac{23 \cdot 20 + 13}{20} - \frac{4 \cdot 20 + 1}{20} = \frac{473}{20} - \frac{81}{20} = \frac{392}{20} = \frac{98}{5} = 19 \frac{3}{5}$$ 6) $13\frac{9}{15} - 3\frac{8}{15} = \frac{13 \cdot 15 + 9}{15} - \frac{3 \cdot 15 + 8}{15} = \frac{204}{15} - \frac{53}{15} = \frac{151}{15} = 10\frac{1}{15}$$ 7) $7\frac{15}{28} - 2\frac{9}{28} = \frac{7 \cdot 28 + 15}{28} - \frac{2 \cdot 28 + 9}{28} = \frac{211}{28} - \frac{65}{28} = \frac{146}{28} = \frac{73}{14} = 5\frac{3}{14}$$ 8) $11\frac{5}{18} - 3\frac{11}{18} = \frac{11 \cdot 18 + 5}{18} - \frac{3 \cdot 18 + 11}{18} = \frac{203}{18} - \frac{65}{18} = \frac{138}{18} = \frac{23}{3} = 7\frac{2}{3}$$ 9) $14\frac{16}{32} - 4\frac{15}{32} = \frac{14 \cdot 32 + 16}{32} - \frac{4 \cdot 32 + 15}{32} = \frac{464}{32} - \frac{143}{32} = \frac{321}{32} = 10\frac{1}{32}$$ 10) $6\frac{3}{54} - 3\frac{15}{54} = \frac{6 \cdot 54 + 3}{54} - \frac{3 \cdot 54 + 15}{54} = \frac{327}{54} - \frac{177}{54} = \frac{150}{54} = \frac{25}{9} = 2\frac{7}{9}$$ 11) $12\frac{5}{16} - 2\frac{7}{16} = \frac{12 \cdot 16 + 5}{16} - \frac{2 \cdot 16 + 7}{16} = \frac{197}{16} - \frac{39}{16} = \frac{158}{16} = \frac{79}{8} = 9\frac{7}{8}$$ 12) $4\frac{4}{21} - 1\frac{18}{21} = \frac{4 \cdot 21 + 4}{21} - \frac{1 \cdot 21 + 18}{21} = \frac{88}{21} - \frac{39}{21} = \frac{49}{21} = \frac{7}{3} = 2\frac{1}{3}$