Помоги мне найти сумму: а) 8/13 + 3/13

- a) \(\frac{8}{13} + \frac{3}{13} = \frac{8+3}{13} = \frac{11}{13}\) - б) \(\frac{31}{60} + \frac{29}{60} = \frac{31+29}{60} = \frac{60}{60} = 1\) - в) \(18 + \frac{4}{19} = \frac{18 \cdot 19}{19} + \frac{4}{19} = \frac{342 + 4}{19} = \frac{346}{19} = 18\frac{4}{19}\) - г) \(23 + \frac{9}{10} = \frac{23 \cdot 10}{10} + \frac{9}{10} = \frac{230 + 9}{10} = \frac{239}{10} = 23\frac{9}{10}\) - д) \(2 \frac{7}{9} + \frac{8}{9} = \frac{2 \cdot 9 + 7}{9} + \frac{8}{9} = \frac{18 + 7}{9} + \frac{8}{9} = \frac{25}{9} + \frac{8}{9} = \frac{25 + 8}{9} = \frac{33}{9} = 3\frac{6}{9} = 3\frac{2}{3}\) - e) \(15 \frac{8}{11} + 4 \frac{3}{11} = 15 + \frac{8}{11} + 4 + \frac{3}{11} = 15 + 4 + \frac{8}{11} + \frac{3}{11} = 19 + \frac{8+3}{11} = 19 + \frac{11}{11} = 19 + 1 = 20\) - ж) \(4 \frac{1}{2} + 3 \frac{1}{4} = \frac{4 \cdot 2 + 1}{2} + \frac{3 \cdot 4 + 1}{4} = \frac{8+1}{2} + \frac{12+1}{4} = \frac{9}{2} + \frac{13}{4} = \frac{9 \cdot 2}{2 \cdot 2} + \frac{13}{4} = \frac{18}{4} + \frac{13}{4} = \frac{18+13}{4} = \frac{31}{4} = 7\frac{3}{4}\) - з) \(5 \frac{1}{7} + 3 \frac{20}{21} = \frac{5 \cdot 7 + 1}{7} + \frac{3 \cdot 21 + 20}{21} = \frac{35 + 1}{7} + \frac{63 + 20}{21} = \frac{36}{7} + \frac{83}{21} = \frac{36 \cdot 3}{7 \cdot 3} + \frac{83}{21} = \frac{108}{21} + \frac{83}{21} = \frac{108 + 83}{21} = \frac{191}{21} = 9\frac{2}{21}\) Надеюсь, теперь тебе стало понятнее, как складывать дроби и смешанные числа!