Найдите значения выражений: 1) 27^(2/3) + (1/16)^(-0.75) - 25^0.5 2) (1/4)^(-1/2) * 25^(1/2) - 81^(1/2) * 125^(-1/3) 3) 49^(-1/2) * (1/7)^(-2) + 2^(-1) * (-2)^(-2) 4) 216^(-1/3) * (1/6)^(-2) - 5^(-1) * (1/25)^(-1/2) 5) (0.027)^(-1/3) - (-1/6)^(-2) + 256^0.75 - 3^(-1) + 5.5^0

1) $27^{2/3} + (\frac{1}{16})^{-0.75} - 25^{0.5} = (3^3)^{2/3} + (16)^{0.75} - (5^2)^{0.5} = 3^2 + (2^4)^{3/4} - 5^1 = 9 + 2^3 - 5 = 9 + 8 - 5 = 12$. 2) $(\frac{1}{4})^{-1/2} \cdot 25^{1/2} - 81^{1/2} \cdot 125^{-1/3} = (4)^{1/2} \cdot \sqrt{25} - \sqrt{81} \cdot (5^3)^{-1/3} = 2 \cdot 5 - 9 \cdot 5^{-1} = 10 - 9/5 = 10 - 1.8 = 8.2$. 3) $49^{-1/2} \cdot (\frac{1}{7})^{-2} + 2^{-1} \cdot (-2)^{-2} = \frac{1}{\sqrt{49}} \cdot 7^2 + \frac{1}{2} \cdot \frac{1}{(-2)^2} = \frac{1}{7} \cdot 49 + \frac{1}{2} \cdot \frac{1}{4} = 7 + \frac{1}{8} = 7.125$. 4) $216^{-1/3} \cdot (\frac{1}{6})^{-2} - 5^{-1} \cdot (\frac{1}{25})^{-1/2} = (6^3)^{-1/3} \cdot 6^2 - \frac{1}{5} \cdot (25)^{1/2} = 6^{-1} \cdot 36 - \frac{1}{5} \cdot 5 = 6 - 1 = 5$. 5) $(0.027)^{-1/3} - (-\frac{1}{6})^{-2} + 256^{0.75} - 3^{-1} + 5.5^0 = (\frac{27}{1000})^{-1/3} - (-6)^2 + (2^8)^{3/4} - \frac{1}{3} + 1 = \frac{10}{3} - 36 + 2^6 - \frac{1}{3} + 1 = \frac{9}{3} - 36 + 64 + 1 = 3 - 36 + 64 + 1 = 32$.