1. Вычислите: (31 - 12) · (32 - 62).

Допущение: Восстановлены условия примеров, которые четко читаются на фото. ### 1 тип. Действия с отрицательными числами 1. $(31 - 12) \cdot (32 - 62) = 19 \cdot (-30) = -570$ 2. $(13 - 44) \cdot (27 - 47) = (-31) \cdot (-20) = 620$ 3. $(87 - 68 - 22) : 3 = (-3) : 3 = -1$ 4. $(12 + 63 - 36) : (-13) = 39 : (-13) = -3$ 5. $32 - 41 + 54 - 73 = -9 + 54 - 73 = 45 - 73 = -28$ 6. $18 - 92 + 108 - 9 = -74 + 108 - 9 = 34 - 9 = 25$ 7. $37 - 29 - 159 - 86 = 8 - 159 - 86 = -151 - 86 = -237$ 8. $-190 + 39 - 84 + 235 = -151 - 84 + 235 = -235 + 235 = 0$ 9. $(53 - 27 - 14) : (41 - 29) = 12 : 12 = 1$ 10. $(123 - 49 - 83) : (186 - 195) = (-9) : (-9) = 1 ### 2 тип. Действия с обыкновенными дробями 1. $(\frac{6}{5} - \frac{3}{4}) \cdot \frac{2}{3} = (\frac{24}{20} - \frac{15}{20}) \cdot \frac{2}{3} = \frac{9}{20} \cdot \frac{2}{3} = \frac{3}{10} = 0,3$ 2. $(\frac{6}{5} - \frac{2}{3}) \cdot \frac{1}{2} = (\frac{18}{15} - \frac{10}{15}) \cdot \frac{1}{2} = \frac{8}{15} \cdot \frac{1}{2} = \frac{4}{15}$ 3. $\frac{11}{18} - \frac{4}{9} - \frac{3}{16} = \frac{22}{36} - \frac{16}{36} - \frac{3}{16} = \frac{6}{36} - \frac{3}{16} = \frac{1}{6} - \frac{3}{16} = \frac{8}{48} - \frac{9}{48} = -\frac{1}{48}$ 4. $\frac{29}{30} - \frac{5}{18} - \frac{6}{25} = \frac{435}{450} - \frac{125}{450} - \frac{108}{450} = \frac{202}{450} = \frac{101}{225}$ 5. $\frac{8}{5} \cdot (\frac{3}{4} + \frac{11}{8}) = \frac{8}{5} \cdot (\frac{6}{8} + \frac{11}{8}) = \frac{8}{5} \cdot \frac{17}{8} = \frac{17}{5} = 3,4$ 6. $\frac{18}{7} \cdot (\frac{4}{9} + \frac{15}{18}) = \frac{18}{7} \cdot (\frac{8}{18} + \frac{15}{18}) = \frac{18}{7} \cdot \frac{23}{18} = \frac{23}{7} = 3\frac{2}{7}$ 7. $\frac{8}{5} \cdot \frac{3}{4} + \frac{11}{8} = \frac{6}{5} + \frac{11}{8} = \frac{48}{40} + \frac{55}{40} = \frac{103}{40} = 2\frac{23}{40} = 2,575$ 8. $2\frac{4}{9} : (\frac{2}{3} - \frac{2}{7}) = \frac{22}{9} : (\frac{14}{21} - \frac{6}{21}) = \frac{22}{9} : \frac{8}{21} = \frac{22}{9} \cdot \frac{21}{8} = \frac{11 \cdot 7}{3 \cdot 4} = \frac{77}{12} = 6\frac{5}{12}$ 9. $1\frac{5}{6} : (\frac{2}{3} - \frac{2}{7}) = \frac{11}{6} : (\frac{14}{21} - \frac{6}{21}) = \frac{11}{6} : \frac{8}{21} = \frac{11}{6} \cdot \frac{21}{8} = \frac{11 \cdot 7}{2 \cdot 8} = \frac{77}{16} = 4\frac{13}{16} = 4,8125$ 10. $\frac{2}{7} + \frac{3}{8} : \frac{7}{32} = \frac{2}{7} + \frac{3}{8} \cdot \frac{32}{7} = \frac{2}{7} + \frac{3 \cdot 4}{7} = \frac{2}{7} + \frac{12}{7} = \frac{14}{7} = 2$ 11. $\frac{35}{24} : \frac{15}{32} - 3 = \frac{35}{24} \cdot \frac{32}{15} - 3 = \frac{7 \cdot 4}{3 \cdot 3} - 3 = \frac{28}{9} - \frac{27}{9} = \frac{1}{9}$