Задание 1. Найдите значение выражения. 1) (5^4)^6 : 5^22

### Задание 1 1) $(5^4)^6 : 5^{22} = 5^{24} : 5^{22} = 5^{24-22} = 5^2 = 25$ 2) $(4^{15})^5 : 4^{73} = 4^{75} : 4^{73} = 4^{75-73} = 4^2 = 16$ 3) $(2^{16})^5 : 2^{74} = 2^{80} : 2^{74} = 2^{80-74} = 2^6 = 64$ 4) $(3^2)^{17} : 3^{31} = 3^{34} : 3^{31} = 3^{34-31} = 3^3 = 27$ ### Задание 2 1) $\frac{(3\sqrt{8})^2}{6} = \frac{9 \cdot 8}{6} = \frac{72}{6} = 12$ 2) $\frac{(5\sqrt{6})^2}{10} = \frac{25 \cdot 6}{10} = \frac{150}{10} = 15$ 3) $\frac{(6\sqrt{2})^2}{8} = \frac{36 \cdot 2}{8} = \frac{72}{8} = 9$ 4) $\frac{(2\sqrt{7})^2}{4} = \frac{4 \cdot 7}{4} = 7$ 5) $(\sqrt{12}-\sqrt{75}) \cdot \sqrt{12} = (2\sqrt{3}-5\sqrt{3}) \cdot 2\sqrt{3} = (-3\sqrt{3}) \cdot 2\sqrt{3} = -6 \cdot 3 = -18$ 6) $(\sqrt{63}-\sqrt{28}) \cdot \sqrt{7} = (3\sqrt{7}-2\sqrt{7}) \cdot \sqrt{7} = (\sqrt{7}) \cdot \sqrt{7} = 7$ 7) $(\sqrt{32}-\sqrt{50}) \cdot \sqrt{8} = (4\sqrt{2}-5\sqrt{2}) \cdot 2\sqrt{2} = (-\sqrt{2}) \cdot 2\sqrt{2} = -2 \cdot 2 = -4$ 8) $(\sqrt{75}-\sqrt{27}) \cdot \sqrt{3} = (5\sqrt{3}-3\sqrt{3}) \cdot \sqrt{3} = 2\sqrt{3} \cdot \sqrt{3} = 2 \cdot 3 = 6$