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Допущение: Читаемость условий достаточна для решения. **Блок 1 (умножение корней)** 1. $5\sqrt{11} \cdot 2\sqrt{2} \cdot \sqrt{22} = 10\sqrt{11 \cdot 2 \cdot 22} = 10\sqrt{484} = 10 \cdot 22 = 220$ 2. $7\sqrt{15} \cdot 2\sqrt{2} \cdot \sqrt{30} = 14\sqrt{15 \cdot 2 \cdot 30} = 14\sqrt{900} = 14 \cdot 30 = 420$ 3. $4\sqrt{17} \cdot 5\sqrt{2} \cdot \sqrt{34} = 20\sqrt{17 \cdot 2 \cdot 34} = 20\sqrt{1156} = 20 \cdot 34 = 680$ 4. $4\sqrt{5} \cdot 3\sqrt{3} \cdot \sqrt{15} = 12\sqrt{5 \cdot 3 \cdot 15} = 12\sqrt{225} = 12 \cdot 15 = 180$ 5. $10\sqrt{7} \cdot 2\sqrt{6} \cdot \sqrt{42} = 20\sqrt{7 \cdot 6 \cdot 42} = 20\sqrt{1764} = 20 \cdot 42 = 840$ 6. $5\sqrt{13} \cdot 2\sqrt{3} \cdot \sqrt{39} = 10\sqrt{13 \cdot 3 \cdot 39} = 10\sqrt{1521} = 10 \cdot 39 = 390$ **Задание 8** 1. $\sqrt{6^4} = 6^{4/2} = 6^2 = 36$ 2. $\sqrt{5^6} = 5^{6/2} = 5^3 = 125$ 3. $\sqrt{4^6} = 4^{6/2} = 4^3 = 64$ 4. $\sqrt{9^3} = \sqrt{729} = 27$ 5. $\sqrt{8^4} = 8^{4/2} = 8^2 = 64$ 6. $\sqrt{3^6} = 3^{6/2} = 3^3 = 27$ 7. $\frac{(2\sqrt{10})^2}{160} = \frac{4 \cdot 10}{160} = \frac{40}{160} = 0,25$ 8. $\frac{(3\sqrt{5})^2}{30} = \frac{9 \cdot 5}{30} = \frac{45}{30} = 1,5$ 9. $\frac{(4\sqrt{2})^2}{64} = \frac{16 \cdot 2}{64} = \frac{32}{64} = 0,5$ 10. $\frac{72}{(2\sqrt{3})^2} = \frac{72}{4 \cdot 3} = \frac{72}{12} = 6$ 11. $\frac{160}{(2\sqrt{5})^2} = \frac{160}{4 \cdot 5} = \frac{160}{20} = 8$ 12. $\frac{200}{(5\sqrt{2})^2} = \frac{200}{25 \cdot 2} = \frac{200}{50} = 4$