2) 2/11 : 4/33 + 3 * 7/12 - 1 7/8 =

Допущение: Восстанавливаю условия примеров по изображению. **Решение примеров:** **2)** $\frac{2}{11} : \frac{4}{33} + 3 \cdot \frac{7}{12} - 1 \frac{7}{8}$ 1) $\frac{2}{11} : \frac{4}{33} = \frac{2}{11} \cdot \frac{33}{4} = \frac{1}{1} \cdot \frac{3}{2} = \frac{3}{2} = 1,5$ 2) $3 \cdot \frac{7}{12} = \frac{3 \cdot 7}{12} = \frac{21}{12} = \frac{7}{4} = 1,75$ 3) $1,5 + 1,75 = 3,25$ 4) $3,25 - 1 \frac{7}{8} = 3,25 - 1,875 = 1,375$ (или $\frac{11}{8}$) **Ответ:** $1 \frac{3}{8}$ (или $1,375$). **3)** $\frac{33}{34} \cdot (1 - \frac{38}{55}) + \frac{13}{20} : \frac{13}{25}$ 1) $1 - \frac{38}{55} = \frac{55-38}{55} = \frac{17}{55}$ 2) $\frac{33}{34} \cdot \frac{17}{55} = \frac{33 \cdot 17}{34 \cdot 55} = \frac{3 \cdot 11 \cdot 17}{2 \cdot 17 \cdot 5 \cdot 11} = \frac{3}{10} = 0,3$ 3) $\frac{13}{20} : \frac{13}{25} = \frac{13}{20} \cdot \frac{25}{13} = \frac{25}{20} = \frac{5}{4} = 1,25$ 4) $0,3 + 1,25 = 1,55$ **Ответ:** $1,55$ (или $1 \frac{11}{20}$). **4)** $(3 \frac{3}{11} - 1 \frac{5}{22}) : \frac{9}{55} : \frac{5}{2} - 3 \frac{4}{7} \cdot \frac{14}{50}$ 1) $3 \frac{3}{11} - 1 \frac{5}{22} = 3 \frac{6}{22} - 1 \frac{5}{22} = 2 \frac{1}{22} = \frac{45}{22}$ 2) $\frac{45}{22} : \frac{9}{55} = \frac{45}{22} \cdot \frac{55}{9} = \frac{5 \cdot 5}{2 \cdot 1} = \frac{25}{2} = 12,5$ 3) $12,5 : 2,5 = 5$ 4) $3 \frac{4}{7} \cdot \frac{14}{50} = \frac{25}{7} \cdot \frac{14}{50} = \frac{1}{1} \cdot \frac{2}{2} = 1$ 5) $5 - 1 = 4$ **Ответ:** $4$. **5)** $(5 \frac{1}{3} + 1 \frac{2}{3}) \cdot \frac{13}{14} + (2 \frac{1}{9} - 1 \frac{1}{6}) : \frac{17}{15}$ 1) $5 \frac{1}{3} + 1 \frac{2}{3} = 6 \frac{3}{3} = 7$ 2) $7 \cdot \frac{13}{14} = \frac{13}{2} = 6,5$ 3) $2 \frac{1}{9} - 1 \frac{1}{6} = 2 \frac{2}{18} - 1 \frac{3}{18} = 1 \frac{20}{18} - 1 \frac{3}{18} = \frac{17}{18}$ 4) $\frac{17}{18} : \frac{17}{15} = \frac{17}{18} \cdot \frac{15}{17} = \frac{15}{18} = \frac{5}{6}$ 5) $6,5 + \frac{5}{6} = 6 \frac{1}{2} + \frac{5}{6} = 6 \frac{3}{6} + \frac{5}{6} = 6 \frac{8}{6} = 7 \frac{2}{6} = 7 \frac{1}{3}$ **Ответ:** $7 \frac{1}{3}$. **6)** $\frac{8}{25} \cdot \frac{45}{12} : (1 \frac{1}{14} - 1 \frac{1}{21}) \cdot \frac{5}{27} + 5 \frac{2}{3}$ 1) $1 \frac{1}{14} - 1 \frac{1}{21} = 1 \frac{3}{42} - 1 \frac{2}{42} = \frac{1}{42}$ 2) $\frac{8}{25} \cdot \frac{45}{12} = \frac{8}{12} \cdot \frac{45}{25} = \frac{2}{3} \cdot \frac{9}{5} = \frac{2}{1} \cdot \frac{3}{5} = \frac{6}{5}$ 3) $\frac{6}{5} : \frac{1}{42} = \frac{6}{5} \cdot 42 = \frac{252}{5} = 50,4$ 4) $50,4 \cdot \frac{5}{27} = \frac{252}{5} \cdot \frac{5}{27} = \frac{252}{27} = 9 \frac{9}{27} = 9 \frac{1}{3}$ 5) $9 \frac{1}{3} + 5 \frac{2}{3} = 14 \frac{3}{3} = 15$ **Ответ:** $15$.