Выполнить действия с обыкновенными дробями:

Привет! Давай решим примеры с дробями.\n\nСтолбик 1:\nа) $\frac{1}{5} + \frac{1}{3} = \frac{3}{15} + \frac{5}{15} = \frac{8}{15}$\nб) $\frac{1}{2} + \frac{3}{8} = \frac{4}{8} + \frac{3}{8} = \frac{7}{8}$\nв) $\frac{3}{4} + 2 = \frac{3}{4} + \frac{8}{4} = \frac{11}{4} = 2\frac{3}{4}$\nг) $\frac{2}{3} - \frac{1}{6} = \frac{4}{6} - \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$\nд) $\frac{7}{12} - 1 = \frac{7}{12} - \frac{12}{12} = -\frac{5}{12}$\nе) $\frac{4}{5} - \frac{9}{10} = \frac{8}{10} - \frac{9}{10} = -\frac{1}{10}$\nё) $\frac{1}{3} - \frac{1}{2} = \frac{2}{6} - \frac{3}{6} = -\frac{1}{6}$\nж) $1 + \frac{7}{3} = \frac{3}{3} + \frac{7}{3} = \frac{10}{3} = 3\frac{1}{3}$\n\nСтолбик 2:\nз) $\frac{8}{15} : 4 = \frac{8}{15} \cdot \frac{1}{4} = \frac{2}{15}$\nи) $3 : \frac{3}{2} = 3 \cdot \frac{2}{3} = 2$\nй) $-1 : \frac{3}{4} = -1 \cdot \frac{4}{3} = -\frac{4}{3} = -1\frac{1}{3}$\nк) $-\frac{7}{12} : (-\frac{1}{4}) = \frac{7}{12} \cdot \frac{4}{1} = \frac{7}{3} = 2\frac{1}{3}$\nл) $\frac{1}{4} \cdot 2 = \frac{2}{4} = \frac{1}{2}$\nм) $-\frac{3}{4} \cdot \frac{4}{9} = -\frac{3}{9} = -\frac{1}{3}$\nн) $\frac{7}{9} \cdot \frac{18}{35} = \frac{1}{1} \cdot \frac{2}{5} = \frac{2}{5}$\nо) $-\frac{4}{19} \cdot (-\frac{57}{64}) = \frac{1}{1} \cdot \frac{3}{16} = \frac{3}{16}$\n\nСтолбик 3:\nп) $2\frac{3}{4} + 3\frac{5}{7} = \frac{11}{4} + \frac{26}{7} = \frac{77+104}{28} = \frac{181}{28} = 6\frac{13}{28}$\nр) $-4\frac{2}{3} + 7\frac{1}{2} = -\frac{14}{3} + \frac{15}{2} = \frac{-28+45}{6} = \frac{17}{6} = 2\frac{5}{6}$\nс) $4\frac{1}{3} + \frac{3}{17} = \frac{13}{3} + \frac{3}{17} = \frac{221+9}{51} = \frac{230}{51} = 4\frac{26}{51}$\nт) $-5\frac{2}{5} + 4\frac{1}{3} = -\frac{27}{5} + \frac{13}{3} = \frac{-81+65}{15} = -\frac{16}{15} = -1\frac{1}{15}$\nу) $6\frac{1}{2} - 3\frac{3}{4} = \frac{13}{2} - \frac{15}{4} = \frac{26-15}{4} = \frac{11}{4} = 2\frac{3}{4}$\nф) $2\frac{1}{2} - 7\frac{5}{6} = \frac{5}{2} - \frac{47}{6} = \frac{15-47}{6} = -\frac{32}{6} = -5\frac{1}{3}$\nх) $-4\frac{2}{3} - 7\frac{7}{9} = -\frac{14}{3} - \frac{70}{9} = \frac{-42-70}{9} = -\frac{112}{9} = -12\frac{4}{9}$\nц) $-2\frac{2}{3} - 3\frac{5}{9} = -\frac{8}{3} - \frac{32}{9} = \frac{-24-32}{9} = -\frac{56}{9} = -6\frac{2}{9}$\n\nСтолбик 4:\nч) $2\frac{3}{4} \cdot 5\frac{7}{33} = \frac{11}{4} \cdot \frac{172}{33} = 1 \cdot \frac{43}{3} = 14\frac{1}{3}$\nш) $-3\frac{1}{2} \cdot 2\frac{2}{5} = -\frac{7}{2} \cdot \frac{12}{5} = -\frac{42}{5} = -8\frac{2}{5}$\nщ) $-4\frac{5}{7} \cdot (-2\frac{6}{11}) = -\frac{33}{7} \cdot (-\frac{28}{11}) = 3 \cdot 4 = 12$\nъ) $-3\frac{1}{2} \cdot 2\frac{2}{7} = -\frac{7}{2} \cdot \frac{16}{7} = -8$\nы) $4\frac{1}{3} : 2\frac{5}{6} = \frac{13}{3} : \frac{17}{6} = \frac{13}{3} \cdot \frac{6}{17} = \frac{26}{17} = 1\frac{9}{17}$\nь) $-7\frac{3}{8} : (-2\frac{1}{16}) = -\frac{59}{8} : (-\frac{33}{16}) = \frac{59}{8} \cdot \frac{16}{33} = \frac{59 \cdot 2}{33} = \frac{118}{33} = 3\frac{19}{33}$\nэ) $-1\frac{1}{3} : 3\frac{1}{6} = -\frac{4}{3} : \frac{19}{6} = -\frac{4}{3} \cdot \frac{6}{19} = -\frac{8}{19}$\nю) $4\frac{1}{5} : 7\frac{1}{25} = \frac{21}{5} : \frac{176}{25} = \frac{21}{5} \cdot \frac{25}{176} = \frac{21 \cdot 5}{176} = \frac{105}{176}$