Привет! Давай решим эти примеры на дроби. Будем выполнять действия строго по порядку: сначала в скобках, затем умножение/деление, в конце сложение/вычитание.
### 1. $2\frac{1}{3} : (\frac{5}{8} - \frac{8}{3}) - 2 \cdot 1\frac{3}{7}$
1) $\frac{5}{8} - \frac{8}{3} = \frac{15}{24} - \frac{64}{24} = -\frac{49}{24}$
2) $\frac{7}{3} : (-\frac{49}{24}) = \frac{7}{3} \cdot (-\frac{24}{49}) = -\frac{1}{1} \cdot \frac{8}{7} = -\frac{8}{7} = -1\frac{1}{7}$
3) $2 \cdot \frac{10}{7} = \frac{20}{7} = 2\frac{6}{7}$
4) $-\frac{8}{7} - \frac{20}{7} = -\frac{28}{7} = -4$
**Ответ: -4**
### 2. $\frac{7}{15} : (\frac{6}{10} - \frac{8}{3}) + 19 \cdot \frac{2}{31}$
1) $\frac{6}{10} - \frac{8}{3} = \frac{3}{5} - \frac{8}{3} = \frac{9}{15} - \frac{40}{15} = -\frac{31}{15}$
2) $\frac{7}{15} : (-\frac{31}{15}) = \frac{7}{15} \cdot (-\frac{15}{31}) = -\frac{7}{31}$
3) $19 \cdot \frac{2}{31} = \frac{38}{31} = 1\frac{7}{31}$
4) $-\frac{7}{31} + \frac{38}{31} = \frac{31}{31} = 1$
**Ответ: 1**
### 3. $(7 - 1\frac{5}{9} : \frac{7}{24}) : \frac{20}{27}$
1) $1\frac{5}{9} : \frac{7}{24} = \frac{14}{9} \cdot \frac{24}{7} = \frac{2}{3} \cdot \frac{8}{1} = \frac{16}{3} = 5\frac{1}{3}$
2) $7 - 5\frac{1}{3} = 6\frac{3}{3} - 5\frac{1}{3} = 1\frac{2}{3} = \frac{5}{3}$
3) $\frac{5}{3} : \frac{20}{27} = \frac{5}{3} \cdot \frac{27}{20} = \frac{1}{1} \cdot \frac{9}{4} = \frac{9}{4} = 2\frac{1}{4}$
**Ответ: 2,25**
### 4. $(1\frac{1}{35} : \frac{4}{5} - 1\frac{8}{35}) \cdot 3\frac{1}{3}$
1) $\frac{36}{35} : \frac{4}{5} = \frac{36}{35} \cdot \frac{5}{4} = \frac{9}{7} = 1\frac{2}{7}$
2) $1\frac{2}{7} - 1\frac{8}{35} = \frac{9}{7} - \frac{43}{35} = \frac{45}{35} - \frac{43}{35} = \frac{2}{35}$
3) $\frac{2}{35} \cdot \frac{10}{3} = \frac{2}{7} \cdot \frac{2}{3} = \frac{4}{21}$
**Ответ: 4/21**
### 5. $1\frac{31}{35} : (2 - \frac{8}{9} : 1\frac{19}{45})$
1) $\frac{8}{9} : \frac{64}{45} = \frac{8}{9} \cdot \frac{45}{64} = \frac{1}{1} \cdot \frac{5}{8} = \frac{5}{8}$
2) $2 - \frac{5}{8} = 1\frac{3}{8} = \frac{11}{8}$
3) $\frac{66}{35} : \frac{11}{8} = \frac{66}{35} \cdot \frac{8}{11} = \frac{6}{35} \cdot 8 = \frac{48}{35} = 1\frac{13}{35}$
**Ответ: 1 13/35**
### 6. $2\frac{7}{9} \cdot \frac{18}{25} + \frac{9}{60} : (\frac{7}{12} - \frac{3}{5})$
1) $\frac{25}{9} \cdot \frac{18}{25} = \frac{1}{1} \cdot \frac{2}{1} = 2$
2) $\frac{7}{12} - \frac{3}{5} = \frac{35}{60} - \frac{36}{60} = -\frac{1}{60}$
3) $\frac{9}{60} : (-\frac{1}{60}) = \frac{3}{20} \cdot (-60) = 3 \cdot (-3) = -9$
4) $2 + (-9) = -7$
**Ответ: -7**
### 7. $(5\frac{1}{16} - 1\frac{1}{8}) (\frac{5}{6} + \frac{3}{14})$
1) $5\frac{1}{16} - 1\frac{2}{16} = 4\frac{17}{16} - 1\frac{2}{16} = 3\frac{15}{16} = \frac{63}{16}$
2) $\frac{5}{6} + \frac{3}{14} = \frac{35}{42} + \frac{9}{42} = \frac{44}{42} = \frac{22}{21}$
3) $\frac{63}{16} \cdot \frac{22}{21} = \frac{3}{8} \cdot \frac{11}{1} = \frac{33}{8} = 4\frac{1}{8}$
**Ответ: 4,125**
### 8. $(\frac{4}{5} + \frac{4}{7}) (3\frac{3}{8} + 2\frac{11}{4})$
1) $\frac{28}{35} + \frac{20}{35} = \frac{48}{35}$
2) $3\frac{3}{8} + 2\frac{22}{8} = 5\frac{25}{8} = 8\frac{1}{8} = \frac{65}{8}$
3) $\frac{48}{35} \cdot \frac{65}{8} = \frac{6}{7} \cdot \frac{13}{1} = \frac{78}{7} = 11\frac{1}{7}$
**Ответ: 11 1/7**
### 9. $(2\frac{13}{48} + 2\frac{5}{12}) : 3\frac{3}{4} - 9\frac{3}{4} : 12$
1) $2\frac{13}{48} + 2\frac{20}{48} = 4\frac{33}{48} = 4\frac{11}{16} = \frac{75}{16}$
2) $\frac{75}{16} : \frac{15}{4} = \frac{75}{16} \cdot \frac{4}{15} = \frac{5}{4} = 1\frac{1}{4}$
3) $9\frac{3}{4} : 12 = \frac{39}{4} : 12 = \frac{39}{48} = \frac{13}{16}$
4) $1\frac{4}{16} - \frac{13}{16} = \frac{20}{16} - \frac{13}{16} = \frac{7}{16}$
**Ответ: 7/16**
### 10. $-3\frac{1}{7} \cdot (-8) - 2,9 : 0,1 + \frac{11}{21} : (-3\frac{2}{3})$
1) $-\frac{22}{7} \cdot (-8) = \frac{176}{7} = 25\frac{1}{7}$
2) $2,9 : 0,1 = 29$
3) $\frac{11}{21} : (-\frac{11}{3}) = \frac{11}{21} \cdot (-\frac{3}{11}) = -\frac{1}{7}$
4) $25\frac{1}{7} - 29 - \frac{1}{7} = 25 - 29 = -4$
**Ответ: -4**
### 11. $4\frac{1}{3} \cdot 5 + 2,4 : (-0,1) - \frac{14}{15} : 1\frac{2}{5}$
1) $\frac{13}{3} \cdot 5 = \frac{65}{3} = 21\frac{2}{3}$
2) $2,4 : (-0,1) = -24$
3) $\frac{14}{15} : \frac{7}{5} = \frac{14}{15} \cdot \frac{5}{7} = \frac{2}{3}$
4) $21\frac{2}{3} - 24 - \frac{2}{3} = 21 - 24 = -3$
**Ответ: -3**
### 12. $(6 - 2\frac{4}{5}) \cdot 3\frac{1}{8} - 1\frac{3}{5} : \frac{1}{4}$
1) $6 - 2\frac{4}{5} = 3\frac{1}{5} = \frac{16}{5}$
2) $\frac{16}{5} \cdot \frac{25}{8} = 2 \cdot 5 = 10$
3) $\frac{8}{5} \cdot 4 = \frac{32}{5} = 6,4$
4) $10 - 6,4 = 3,6$
**Ответ: 3,6**
### 13. $3\frac{1}{7} \cdot (-4) - 1,8 : (-0,1) + \frac{20}{21} : 1\frac{2}{3}$
1) $\frac{22}{7} \cdot (-4) = -\frac{88}{7} = -12\frac{4}{7}$
2) $1,8 : (-0,1) = -18$
3) $\frac{20}{21} : \frac{5}{3} = \frac{20}{21} \cdot \frac{3}{5} = \frac{4}{7}$
4) $-12\frac{4}{7} - (-18) + \frac{4}{7} = -12\frac{4}{7} + 18 + \frac{4}{7} = -12 + 18 = 6$
**Ответ: 6**
### 14. $4\frac{1}{6} \cdot (1\frac{1}{2} - \frac{3}{5}) + (\frac{3}{4} + \frac{5}{6}) \cdot 6$
1) $1\frac{5}{10} - \frac{6}{10} = \frac{15}{10} - \frac{6}{10} = \frac{9}{10}$
2) $\frac{25}{6} \cdot \frac{9}{10} = \frac{5}{2} \cdot \frac{3}{2} = \frac{15}{4} = 3\frac{3}{4}$
3) $\frac{9}{12} + \frac{10}{12} = \frac{19}{12}$
4) $\frac{19}{12} \cdot 6 = \frac{19}{2} = 9,5$
5) $3,75 + 9,5 = 13,25$
**Ответ: 13,25**
### 15. $\frac{7}{9} : 1\frac{1}{6} + 2,7 : (-0,1) - 4\frac{1}{3} \cdot (-4)$
1) $\frac{7}{9} : \frac{7}{6} = \frac{7}{9} \cdot \frac{6}{7} = \frac{2}{3}$
2) $2,7 : (-0,1) = -27$
3) $\frac{13}{3} \cdot (-4) = -\frac{52}{3} = -17\frac{1}{3}$
4) $\frac{2}{3} - 27 - (-17\frac{1}{3}) = \frac{2}{3} - 27 + 17\frac{1}{3} = 18 - 27 = -9$
**Ответ: -9**
### 16. $7 \cdot 2\frac{6}{7} + \frac{53}{12} : (\frac{7}{9} - \frac{9}{4})$
1) $7 \cdot \frac{20}{7} = 20$
2) $\frac{7}{9} - \frac{9}{4} = \frac{28}{36} - \frac{81}{36} = -\frac{53}{36}$
3) $\frac{53}{12} : (-\frac{53}{36}) = \frac{53}{12} \cdot (-\frac{36}{53}) = -\frac{36}{12} = -3$
4) $20 - 3 = 17$
**Ответ: 17**