Вопрос:

Реши пример 1) 14/20 + 2 15/27

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Ответ ассистента

Конечно, давай решим эти примеры по порядку! 1) $\frac{14}{20} + 2\frac{15}{27} = \frac{7}{10} + \frac{69}{27} = \frac{7}{10} + \frac{23}{9} = \frac{63}{90} + \frac{230}{90} = \frac{293}{90} = 3\frac{23}{90}$ 2) $(2\frac{1}{15} - \frac{12}{15}) \cdot \frac{1}{34} = (\frac{31}{15} - \frac{12}{15}) \cdot \frac{1}{34} = \frac{19}{15} \cdot \frac{1}{34} = \frac{19}{510} = \frac{1}{30}$ 3) $(2\frac{4}{10} + 1\frac{13}{20}) \cdot \frac{4}{9} = (2\frac{8}{20} + 1\frac{13}{20}) \cdot \frac{4}{9} = \frac{61}{20} \cdot \frac{4}{9} = \frac{61}{5} \cdot \frac{1}{9} = \frac{61}{45} = 1\frac{16}{45}$ 4) $(\frac{8}{16} - \frac{3}{18}) \cdot 12 = (\frac{1}{2} - \frac{1}{6}) \cdot 12 = (\frac{3}{6} - \frac{1}{6}) \cdot 12 = \frac{2}{6} \cdot 12 = \frac{1}{3} \cdot 12 = 4$ 5) $(1\frac{3}{20} + 2\frac{7}{10}) \cdot \frac{3}{11} = (1\frac{3}{20} + 2\frac{14}{20}) \cdot \frac{3}{11} = 3\frac{17}{20} \cdot \frac{3}{11} = \frac{77}{20} \cdot \frac{3}{11} = \frac{7}{20} \cdot 3 = \frac{21}{20} = 1\frac{1}{20}$ 6) $1\frac{8}{16} : (4\frac{13}{14} + \frac{3}{7}) = 1\frac{1}{2} : (4\frac{13}{14} + \frac{6}{14}) = \frac{3}{2} : \frac{69}{14} = \frac{3}{2} \cdot \frac{14}{69} = \frac{1}{1} \cdot \frac{7}{23} = \frac{7}{23}$ 7) $1\frac{17}{34} : (8\frac{1}{6} + 2\frac{6}{24}) = 1\frac{1}{2} : (8\frac{1}{6} + 2\frac{1}{4}) = \frac{3}{2} : (8\frac{2}{12} + 2\frac{3}{12}) = \frac{3}{2} : 10\frac{5}{12} = \frac{3}{2} : \frac{125}{12} = \frac{3}{2} \cdot \frac{12}{125} = \frac{3}{1} \cdot \frac{6}{125} = \frac{18}{125}$ 8) $2\frac{11}{36} : (1\frac{3}{27} + 3\frac{10}{20}) = 2\frac{11}{36} : (1\frac{1}{9} + 3\frac{1}{2}) = \frac{83}{36} : (1\frac{2}{18} + 3\frac{9}{18}) = \frac{83}{36} : 4\frac{11}{18} = \frac{83}{36} : \frac{83}{18} = \frac{83}{36} \cdot \frac{18}{83} = \frac{1}{2} \cdot \frac{1}{1} = \frac{1}{2}$ 9) $2\frac{3}{5} : (1\frac{12}{30} - 1\frac{10}{27}) = \frac{13}{5} : (1\frac{2}{5} - 1\frac{10}{27}) = \frac{13}{5} : (\frac{7}{5} - \frac{37}{27}) = \frac{13}{5} : (\frac{189}{135} - \frac{185}{135}) = \frac{13}{5} : \frac{4}{135} = \frac{13}{5} \cdot \frac{135}{4} = \frac{13}{1} \cdot \frac{27}{4} = \frac{351}{4} = 87\frac{3}{4}$ 10) $18\frac{1}{5} : (2\frac{12}{30} - 2\frac{5}{6}) = 18\frac{1}{5} : (2\frac{2}{5} - 2\frac{5}{6}) = \frac{91}{5} : (\frac{12}{5} - \frac{17}{6}) = \frac{91}{5} : (\frac{72}{30} - \frac{85}{30}) = \frac{91}{5} : (\frac{-13}{30}) = \frac{91}{5} \cdot \frac{-30}{13} = \frac{7}{1} \cdot \frac{-6}{1} = -42$

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