Конечно, я помогу тебе решить эти примеры! Здесь много вычислений с дробями, но мы справимся.
1. $\frac{2}{11} + \frac{9}{11} = \frac{2+9}{11} = \frac{11}{11} = 1$
3. $\frac{12}{17} - \frac{5}{17} = \frac{12-5}{17} = \frac{7}{17}$
4. $5\frac{7}{12} + 5\frac{1}{12} = (5+5) + (\frac{7}{12} + \frac{1}{12}) = 10 + \frac{8}{12} = 10 + \frac{2}{3} = 10\frac{2}{3}$
5. $4\frac{1}{6} + 10 = 14\frac{1}{6}$
6. $8\frac{9}{13} + 2\frac{5}{13} = (8+2) + (\frac{9}{13} + \frac{5}{13}) = 10 + \frac{14}{13} = 10 + 1\frac{1}{13} = 11\frac{1}{13}$
7. $5 - 3\frac{3}{5} = 4\frac{5}{5} - 3\frac{3}{5} = (4-3) + (\frac{5}{5} - \frac{3}{5}) = 1 + \frac{2}{5} = 1\frac{2}{5}$
8. $6\frac{14}{17} - 3\frac{2}{17} + 2\frac{5}{17} = (6-3+2) + (\frac{14}{17} - \frac{2}{17} + \frac{5}{17}) = 5 + \frac{17}{17} = 5 + 1 = 6$
9. $\frac{25}{33} + 5\frac{13}{33} - 4\frac{5}{33} = (5-4) + (\frac{25}{33} + \frac{13}{33} - \frac{5}{33}) = 1 + \frac{33}{33} = 1 + 1 = 2$
10. $9\frac{1}{6} - 3\frac{5}{18} = 9\frac{3}{18} - 3\frac{5}{18} = (9-3) + (\frac{3}{18} - \frac{5}{18}) = 6 - \frac{2}{18} = 5 + 1 - \frac{1}{9} = 5 + \frac{9}{9} - \frac{1}{9} = 5\frac{8}{9}$
11. $5\frac{1}{8} + 14\frac{7}{12} = 5\frac{3}{24} + 14\frac{14}{24} = (5+14) + (\frac{3}{24} + \frac{14}{24}) = 19 + \frac{17}{24} = 19\frac{17}{24}$
12. $5\frac{2}{3} - 3\frac{1}{5} = 5\frac{10}{15} - 3\frac{3}{15} = (5-3) + (\frac{10}{15} - \frac{3}{15}) = 2 + \frac{7}{15} = 2\frac{7}{15}$
13. $3\frac{5}{16} - \frac{1}{4} - 1\frac{1}{16} = 3\frac{5}{16} - \frac{4}{16} - 1\frac{1}{16} = (3-1) + (\frac{5}{16} - \frac{4}{16} - \frac{1}{16}) = 2 + 0 = 2$
14. $\frac{1}{8} + 1\frac{3}{5} + \frac{7}{8} = (\frac{1}{8} + \frac{7}{8}) + 1\frac{3}{5} = 1 + 1\frac{3}{5} = 2\frac{3}{5}$
15. $\frac{1}{3} \cdot \frac{2}{5} = \frac{1 \cdot 2}{3 \cdot 5} = \frac{2}{15}$
16. $\frac{11}{12} \cdot \frac{4}{22} = \frac{11 \cdot 4}{12 \cdot 22} = \frac{1 \cdot 1}{3 \cdot 2} = \frac{1}{6}$
17. $\frac{7}{15} + \frac{1}{15} + \frac{6}{15} = \frac{7+1+6}{15} = \frac{14}{15}$
18. $\frac{13}{23} - \frac{4}{23} - \frac{1}{23} = \frac{13-4-1}{23} = \frac{8}{23}$
19. $2\frac{1}{2} + 7 = 9\frac{1}{2}$
20. $7\frac{5}{7} + 4\frac{2}{7} = (7+4) + (\frac{5}{7} + \frac{2}{7}) = 11 + \frac{7}{7} = 11 + 1 = 12$
21. $4 - \frac{3}{7} = 3\frac{7}{7} - \frac{3}{7} = 3\frac{4}{7}$
22. $4\frac{3}{5} - 1\frac{4}{5} = 3\frac{8}{5} - 1\frac{4}{5} = (3-1) + (\frac{8}{5} - \frac{4}{5}) = 2 + \frac{4}{5} = 2\frac{4}{5}$
23. $8\frac{1}{5} + 2\frac{2}{5} - 3 = (8+2-3) + (\frac{1}{5} + \frac{2}{5}) = 7 + \frac{3}{5} = 7\frac{3}{5}$
24. $9\frac{1}{6} + 3\frac{5}{18} = 9\frac{3}{18} + 3\frac{5}{18} = (9+3) + (\frac{3}{18} + \frac{5}{18}) = 12 + \frac{8}{18} = 12 + \frac{4}{9} = 12\frac{4}{9}$
25. $0\frac{5}{8} - 2\frac{7}{16} = 10\frac{10}{8} - 2\frac{7}{16} = (10-2) + (\frac{10}{8} - \frac{7}{16}) = 8 + (\frac{20}{16} - \frac{7}{16}) = 8 + \frac{13}{16} = 8\frac{13}{16}$
26. $8\frac{5}{9} + 3\frac{5}{6} = 8\frac{10}{18} + 3\frac{15}{18} = (8+3) + (\frac{10}{18} + \frac{15}{18}) = 11 + \frac{25}{18} = 11 + 1\frac{7}{18} = 12\frac{7}{18}$
27. $2\frac{5}{12} - 8\frac{7}{18} = 2\frac{15}{36} - 8\frac{14}{36} = (12-8) + (\frac{15}{36} - \frac{14}{36}) = 4 + \frac{1}{36} = 4\frac{1}{36}$
28. $5\frac{11}{12} - 2\frac{1}{6} - 1\frac{1}{4} = 5\frac{11}{12} - 2\frac{2}{12} - 1\frac{3}{12} = (5-2-1) + (\frac{11}{12} - \frac{2}{12} - \frac{3}{12}) = 2 + \frac{6}{12} = 2 + \frac{1}{2} = 2\frac{1}{2}$
29. $2\frac{7}{9} - 1\frac{5}{18} + 5\frac{1}{2} = 2\frac{14}{18} - 1\frac{5}{18} + 5\frac{9}{18} = (2-1+5) + (\frac{14}{18} - \frac{5}{18} + \frac{9}{18}) = 6 + \frac{18}{18} = 6 + 1 = 7$
30. $\frac{1}{2} \cdot \frac{4}{7} = \frac{1 \cdot 4}{2 \cdot 7} = \frac{4}{14} = \frac{2}{7}$
31. $\frac{17}{26} \cdot \frac{13}{34} = \frac{17 \cdot 13}{26 \cdot 34} = \frac{1 \cdot 1}{2 \cdot 2} = \frac{1}{4}$
