Вопрос:

Выполни сложение смешанных чисел: 91 1/6 + 3 5/18

Фотография

Ответ ассистента

a) $91\frac{1}{6} + 3\frac{5}{18} = 91 + \frac{1}{6} + 3 + \frac{5}{18} = (91+3) + (\frac{1}{6} + \frac{5}{18}) = 94 + (\frac{3}{18} + \frac{5}{18}) = 94 + \frac{8}{18} = 94 + \frac{4}{9} = 94\frac{4}{9}$ б) $1\frac{4}{15} + 2\frac{3}{20} = 1 + \frac{4}{15} + 2 + \frac{3}{20} = (1 + 2) + (\frac{4}{15} + \frac{3}{20}) = 3 + (\frac{16}{60} + \frac{9}{60}) = 3 + \frac{25}{60} = 3 + \frac{5}{12} = 3\frac{5}{12}$ в) $5\frac{1}{8} + 41\frac{7}{12} = 5 + \frac{1}{8} + 41 + \frac{7}{12} = (5+41) + (\frac{1}{8} + \frac{7}{12}) = 46 + (\frac{3}{24} + \frac{14}{24}) = 46 + \frac{17}{24} = 46\frac{17}{24}$ г) $39\frac{5}{6} + 12\frac{5}{9} = 39 + \frac{5}{6} + 12 + \frac{5}{9} = (39 + 12) + (\frac{5}{6} + \frac{5}{9}) = 51 + (\frac{15}{18} + \frac{10}{18}) = 51 + \frac{25}{18} = 51 + 1\frac{7}{18} = 52\frac{7}{18}$ д) $36\frac{5}{7} + 12\frac{7}{8} = 36 + \frac{5}{7} + 12 + \frac{7}{8} = (36 + 12) + (\frac{5}{7} + \frac{7}{8}) = 48 + (\frac{40}{56} + \frac{49}{56}) = 48 + \frac{89}{56} = 48 + 1\frac{33}{56} = 49\frac{33}{56}$ е) $5\frac{2}{3} + 4\frac{3}{8} = 5 + \frac{2}{3} + 4 + \frac{3}{8} = (5 + 4) + (\frac{2}{3} + \frac{3}{8}) = 9 + (\frac{16}{24} + \frac{9}{24}) = 9 + \frac{25}{24} = 9 + 1\frac{1}{24} = 10\frac{1}{24}$ ж) $4\frac{8}{9} + 3\frac{7}{9} = 4 + \frac{8}{9} + 3 + \frac{7}{9} = (4 + 3) + (\frac{8}{9} + \frac{7}{9}) = 7 + \frac{15}{9} = 7 + 1\frac{6}{9} = 8\frac{6}{9} = 8\frac{2}{3}$ з) $8\frac{7}{9} + 3 = 8 + \frac{7}{9} + 3 = (8 + 3) + \frac{7}{9} = 11 + \frac{7}{9} = 11\frac{7}{9}$

Другие решения

Что ещё задавали пользователи