Реши все пункты упражнения

- в) $8^{\frac{2}{3}} = (2^3)^{\frac{2}{3}} = 2^{3 \cdot \frac{2}{3}} = 2^2 = 4$ $16^{-\frac{3}{2}} = (2^4)^{-\frac{3}{2}} = 2^{4 \cdot (-\frac{3}{2})} = 2^{-6} = \frac{1}{2^6} = \frac{1}{64}$ $64^{\frac{5}{6}} = (2^6)^{\frac{5}{6}} = 2^{6 \cdot \frac{5}{6}} = 2^5 = 32$ $32^{-0.4} = 32^{-\frac{2}{5}} = (2^5)^{-\frac{2}{5}} = 2^{5 \cdot (-\frac{2}{5})} = 2^{-2} = \frac{1}{2^2} = \frac{1}{4}$ - г) $\left(\frac{2}{7}\right)^{-2} \cdot \left(\frac{49}{25}\right)^{\frac{1}{2}} = \left(\frac{7}{2}\right)^{2} \cdot \sqrt{\frac{49}{25}} = \frac{49}{4} \cdot \frac{7}{5} = \frac{343}{20} = 17,15$ - д) $(0,01)^{\frac{1}{2}} \cdot (6,25)^{-0,5} = (0,01)^{\frac{1}{2}} \cdot (6,25)^{-\frac{1}{2}} = \sqrt{0,01} \cdot \frac{1}{\sqrt{6,25}} = 0,1 \cdot \frac{1}{2,5} = 0,1 \cdot \frac{10}{25} = \frac{1}{10} \cdot \frac{2}{5} = \frac{2}{50} = \frac{1}{25} = 0,04$ **Ответ:** - в) $4, \frac{1}{64}, 32, \frac{1}{4}$ - г) $17,15$ - д) $0,04$