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Привет! Давай решим эти примеры с дробями.

Первая часть: "Найдите разность"

а) $\frac{1}{9} - \frac{1}{81}$ $$ \frac{1}{9} - \frac{1}{81} = \frac{9}{81} - \frac{1}{81} = \frac{9-1}{81} = \frac{8}{81} $$

б) $\frac{19}{20} - \frac{3}{4}$ $$ \frac{19}{20} - \frac{3}{4} = \frac{19}{20} - \frac{15}{20} = \frac{19-15}{20} = \frac{4}{20} = \frac{1}{5} $$

в) $\frac{11}{15} - \frac{2}{5}$ $$ \frac{11}{15} - \frac{2}{5} = \frac{11}{15} - \frac{6}{15} = \frac{11-6}{15} = \frac{5}{15} = \frac{1}{3} $$

г) $\frac{13}{16} - \frac{3}{4}$ $$ \frac{13}{16} - \frac{3}{4} = \frac{13}{16} - \frac{12}{16} = \frac{13-12}{16} = \frac{1}{16} $$

а) $\frac{7}{12} - \frac{5}{36}$ $$ \frac{7}{12} - \frac{5}{36} = \frac{21}{36} - \frac{5}{36} = \frac{21-5}{36} = \frac{16}{36} = \frac{4}{9} $$

б) $\frac{10}{13} - \frac{4}{52}$ $$ \frac{10}{13} - \frac{4}{52} = \frac{40}{52} - \frac{4}{52} = \frac{40-4}{52} = \frac{36}{52} = \frac{9}{13} $$

в) $\frac{13}{42} - \frac{3}{14}$ $$ \frac{13}{42} - \frac{3}{14} = \frac{13}{42} - \frac{9}{42} = \frac{13-9}{42} = \frac{4}{42} = \frac{2}{21} $$

г) $\frac{31}{48} - \frac{7}{12}$ $$ \frac{31}{48} - \frac{7}{12} = \frac{31}{48} - \frac{28}{48} = \frac{31-28}{48} = \frac{3}{48} = \frac{1}{16} $$

а) $\frac{32}{39} - \frac{2}{13}$ $$ \frac{32}{39} - \frac{2}{13} = \frac{32}{39} - \frac{6}{39} = \frac{32-6}{39} = \frac{26}{39} = \frac{2}{3} $$

б) $\frac{15}{56} - \frac{3}{14}$ $$ \frac{15}{56} - \frac{3}{14} = \frac{15}{56} - \frac{12}{56} = \frac{15-12}{56} = \frac{3}{56} $$

в) $\frac{4}{15} - \frac{1}{60}$ $$ \frac{4}{15} - \frac{1}{60} = \frac{16}{60} - \frac{1}{60} = \frac{16-1}{60} = \frac{15}{60} = \frac{1}{4} $$

г) $\frac{3}{16} - \frac{1}{48}$ $$ \frac{3}{16} - \frac{1}{48} = \frac{9}{48} - \frac{1}{48} = \frac{9-1}{48} = \frac{8}{48} = \frac{1}{6} $$

a) $\frac{25}{34} - \frac{4}{17}$ $$ \frac{25}{34} - \frac{4}{17} = \frac{25}{34} - \frac{8}{34} = \frac{25-8}{34} = \frac{17}{34} = \frac{1}{2} $$

б) $\frac{17}{18} - \frac{7}{54}$ $$ \frac{17}{18} - \frac{7}{54} = \frac{51}{54} - \frac{7}{54} = \frac{51-7}{54} = \frac{44}{54} = \frac{22}{27} $$

в) $\frac{11}{19} - \frac{43}{76}$ $$ \frac{11}{19} - \frac{43}{76} = \frac{44}{76} - \frac{43}{76} = \frac{44-43}{76} = \frac{1}{76} $$

г) $\frac{49}{75} - \frac{8}{25}$ $$ \frac{49}{75} - \frac{8}{25} = \frac{49}{75} - \frac{24}{75} = \frac{49-24}{75} = \frac{25}{75} = \frac{1}{3} $$

Вторая часть: "Вычислите"

а) $\frac{3}{4} - \frac{2}{7}$ $$ \frac{3}{4} - \frac{2}{7} = \frac{21}{28} - \frac{8}{28} = \frac{21-8}{28} = \frac{13}{28} $$

б) $\frac{1}{2} + \frac{3}{7}$ $$ \frac{1}{2} + \frac{3}{7} = \frac{7}{14} + \frac{6}{14} = \frac{7+6}{14} = \frac{13}{14} $$

в) $\frac{2}{9} + \frac{3}{7}$ $$ \frac{2}{9} + \frac{3}{7} = \frac{14}{63} + \frac{27}{63} = \frac{14+27}{63} = \frac{41}{63} $$

г) $\frac{8}{9} - \frac{1}{2}$ $$ \frac{8}{9} - \frac{1}{2} = \frac{16}{18} - \frac{9}{18} = \frac{16-9}{18} = \frac{7}{18} $$

a) $\frac{9}{10} - \frac{1}{15}$ $$ \frac{9}{10} - \frac{1}{15} = \frac{27}{30} - \frac{2}{30} = \frac{27-2}{30} = \frac{25}{30} = \frac{5}{6} $$

б) $\frac{5}{16} + \frac{5}{12}$ $$ \frac{5}{16} + \frac{5}{12} = \frac{15}{48} + \frac{20}{48} = \frac{15+20}{48} = \frac{35}{48} $$

в) $\frac{2}{15} + \frac{3}{20}$ $$ \frac{2}{15} + \frac{3}{20} = \frac{8}{60} + \frac{9}{60} = \frac{8+9}{60} = \frac{17}{60} $$

г) $\frac{14}{15} - \frac{7}{25}$ $$ \frac{14}{15} - \frac{7}{25} = \frac{70}{75} - \frac{21}{75} = \frac{70-21}{75} = \frac{49}{75} $$

Все решено! Если что-то непонятно, спрашивай.