Выполните деление смешанных чисел, предварительно представив их в виде неправильных дробей.

Задание 5 2) $7\frac{3}{13} : 4\frac{4}{9} = \frac{94}{13} : \frac{40}{9} = \frac{94}{13} \cdot \frac{9}{40} = \frac{47 \cdot 9}{13 \cdot 20} = \frac{423}{260} = 1\frac{163}{260}$ 3) $8\frac{4}{7} : 3\frac{2}{5} = \frac{60}{7} : \frac{17}{5} = \frac{60}{7} \cdot \frac{5}{17} = \frac{300}{119} = 2\frac{62}{119}$ 4) $3\frac{7}{11} : 1\frac{14}{33} = \frac{40}{11} : \frac{47}{33} = \frac{40}{11} \cdot \frac{33}{47} = \frac{40 \cdot 3}{47} = \frac{120}{47} = 2\frac{26}{47}$ Задание 6 1) $5 : \frac{9}{5} = \frac{5}{1} \cdot \frac{5}{9} = \frac{25}{9} = 2\frac{7}{9}$ 2) $16 : \frac{3}{4} = \frac{16}{1} \cdot \frac{4}{3} = \frac{64}{3} = 21\frac{1}{3}$ 3) $12 : \frac{4}{5} = \frac{12}{1} \cdot \frac{5}{4} = 3 \cdot 5 = 15$ 4) $7 : \frac{49}{6} = \frac{7}{1} \cdot \frac{6}{49} = \frac{1 \cdot 6}{7} = \frac{6}{7}$ Задание 7 1) $\frac{17}{50} \cdot \frac{15}{34} = \frac{17}{50} \cdot \frac{15}{34} = \frac{1 \cdot 3}{10 \cdot 2} = \frac{3}{20}$ 2) $2\frac{4}{21} : 3\frac{2}{7} = \frac{46}{21} : \frac{23}{7} = \frac{46}{21} \cdot \frac{7}{23} = \frac{2 \cdot 1}{3 \cdot 1} = \frac{2}{3}$ 3) $\frac{5}{13} \cdot 26 = \frac{5 \cdot 26}{13} = 5 \cdot 2 = 10$ 4) $9\frac{3}{4} : 11\frac{7}{10} = \frac{39}{4} : \frac{117}{10} = \frac{39}{4} \cdot \frac{10}{117} = \frac{1 \cdot 5}{2 \cdot 3} = \frac{5}{6}$