Найдите сумму: 1) 14 1/4 + 7 5/6

50. Найдите сумму: 1) $14\frac{1}{4} + 7\frac{5}{6} = 14 + \frac{1}{4} + 7 + \frac{5}{6} = (14+7) + (\frac{1}{4} + \frac{5}{6}) = 21 + (\frac{3}{12} + \frac{10}{12}) = 21 + \frac{13}{12} = 21 + 1\frac{1}{12} = 22\frac{1}{12}$ 2) $4\frac{11}{18} + 8\frac{7}{12} = 4 + \frac{11}{18} + 8 + \frac{7}{12} = (4+8) + (\frac{11}{18} + \frac{7}{12}) = 12 + (\frac{22}{36} + \frac{21}{36}) = 12 + \frac{43}{36} = 12 + 1\frac{7}{36} = 13\frac{7}{36}$ 3) $7\frac{5}{24} + 2\frac{3}{16} = 7 + \frac{5}{24} + 2 + \frac{3}{16} = (7+2) + (\frac{5}{24} + \frac{3}{16}) = 9 + (\frac{10}{48} + \frac{9}{48}) = 9 + \frac{19}{48}$ 4) $7\frac{5}{16} + 4\frac{1}{6} + 3\frac{3}{8} = 7 + \frac{5}{16} + 4 + \frac{1}{6} + 3 + \frac{3}{8} = (7+4+3) + (\frac{5}{16} + \frac{1}{6} + \frac{3}{8}) = 14 + (\frac{15}{48} + \frac{8}{48} + \frac{18}{48}) = 14 + \frac{41}{48}$ 51. Найдите разность: 1) $8\frac{7}{8} - 5\frac{3}{4} = 8 + \frac{7}{8} - 5 - \frac{3}{4} = (8-5) + (\frac{7}{8} - \frac{3}{4}) = 3 + (\frac{7}{8} - \frac{6}{8}) = 3 + \frac{1}{8} = 3\frac{1}{8}$ 2) $7\frac{7}{15} - 4\frac{5}{18} = 7 + \frac{7}{15} - 4 - \frac{5}{18} = (7-4) + (\frac{7}{15} - \frac{5}{18}) = 3 + (\frac{42}{90} - \frac{25}{90}) = 3 + \frac{17}{90} = 3\frac{17}{90}$ 3) $16\frac{11}{18} - 8\frac{8}{27} = 16 + \frac{11}{18} - 8 - \frac{8}{27} = (16-8) + (\frac{11}{18} - \frac{8}{27}) = 8 + (\frac{33}{54} - \frac{16}{54}) = 8 + \frac{17}{54} = 8\frac{17}{54}$ 4) $8\frac{17}{28} - 7\frac{23}{42} = 8 + \frac{17}{28} - 7 - \frac{23}{42} = (8-7) + (\frac{17}{28} - \frac{23}{42}) = 1 + (\frac{51}{84} - \frac{46}{84}) = 1 + \frac{5}{84} = 1\frac{5}{84}$