Заполни таблицу для функции g(x) = 8/9x - 1/9.

Чтобы заполнить таблицу для функции $g(x) = \frac{8}{9}x - \frac{1}{9}$, нужно подставить значения $x$ в формулу и вычислить $g(x)$ для каждого $x$: * $x = -5$: $g(-5) = \frac{8}{9}(-5) - \frac{1}{9} = \frac{-40}{9} - \frac{1}{9} = \frac{-41}{9} \approx -4.56$ * $x = -4$: $g(-4) = \frac{8}{9}(-4) - \frac{1}{9} = \frac{-32}{9} - \frac{1}{9} = \frac{-33}{9} \approx -3.67$ * $x = -3$: $g(-3) = \frac{8}{9}(-3) - \frac{1}{9} = \frac{-24}{9} - \frac{1}{9} = \frac{-25}{9} \approx -2.78$ * $x = -2$: $g(-2) = \frac{8}{9}(-2) - \frac{1}{9} = \frac{-16}{9} - \frac{1}{9} = \frac{-17}{9} \approx -1.89$ * $x = -1$: $g(-1) = \frac{8}{9}(-1) - \frac{1}{9} = \frac{-8}{9} - \frac{1}{9} = \frac{-9}{9} = -1$ * $x = 0$: $g(0) = \frac{8}{9}(0) - \frac{1}{9} = 0 - \frac{1}{9} = -\frac{1}{9} \approx -0.11$ * $x = 1$: $g(1) = \frac{8}{9}(1) - \frac{1}{9} = \frac{8}{9} - \frac{1}{9} = \frac{7}{9} \approx 0.78$ * $x = 2$: $g(2) = \frac{8}{9}(2) - \frac{1}{9} = \frac{16}{9} - \frac{1}{9} = \frac{15}{9} \approx 1.67$ * $x = 3$: $g(3) = \frac{8}{9}(3) - \frac{1}{9} = \frac{24}{9} - \frac{1}{9} = \frac{23}{9} \approx 2.56$ * $x = 4$: $g(4) = \frac{8}{9}(4) - \frac{1}{9} = \frac{32}{9} - \frac{1}{9} = \frac{31}{9} \approx 3.44$ * $x = 5$: $g(5) = \frac{8}{9}(5) - \frac{1}{9} = \frac{40}{9} - \frac{1}{9} = \frac{39}{9} \approx 4.33$ Получаем таблицу: | x | -5 | -4 | -3 | -2 | -1 | 0 | 1 | 2 | 3 | 4 | 5 | | --- | ----- | ----- | ----- | ----- | ---- | ----- | ---- | ---- | ---- | ---- | ---- | | g(x) | -4.56 | -3.67 | -2.78 | -1.89 | -1 | -0.11 | 0.78 | 1.67 | 2.56 | 3.44 | 4.33 |