Выполни действия с дробями

Задание 4. а) $\frac{7}{10} + \frac{1}{10} = \frac{8}{10} = \frac{4}{5}$ б) $\frac{7}{12} + \frac{1}{4} = \frac{7}{12} + \frac{3}{12} = \frac{10}{12} = \frac{5}{6}$ в) $\frac{1}{5} + \frac{2}{15} = \frac{3}{15} + \frac{2}{15} = \frac{5}{15} = \frac{1}{3}$ г) $\frac{5}{6} + \frac{1}{9} = \frac{15}{18} + \frac{2}{18} = \frac{17}{18}$ д) $\frac{2}{9} + \frac{1}{12} = \frac{8}{36} + \frac{3}{36} = \frac{11}{36}$ е) $\frac{7}{24} + \frac{1}{60} = \frac{35}{120} + \frac{2}{120} = \frac{37}{120}$ ж) $\frac{1}{42} + \frac{2}{63} = \frac{3}{126} + \frac{4}{126} = \frac{7}{126} = \frac{1}{18}$ з) $\frac{5}{12} + \frac{3}{20} = \frac{25}{60} + \frac{9}{60} = \frac{34}{60} = \frac{17}{30}$ Задание 5. а) $\frac{7}{8} - \frac{3}{4} = \frac{7}{8} - \frac{6}{8} = \frac{1}{8}$ б) $\frac{9}{10} - \frac{2}{5} = \frac{9}{10} - \frac{4}{10} = \frac{5}{10} = \frac{1}{2}$ в) $\frac{3}{5} - \frac{4}{15} = \frac{9}{15} - \frac{4}{15} = \frac{5}{15} = \frac{1}{3}$ г) $\frac{7}{8} - \frac{6}{7} = \frac{49}{56} - \frac{48}{56} = \frac{1}{56}$ д) $\frac{7}{12} - \frac{8}{15} = \frac{35}{60} - \frac{32}{60} = \frac{3}{60} = \frac{1}{20}$ е) $\frac{25}{39} - \frac{15}{26} = \frac{50}{78} - \frac{45}{78} = \frac{5}{78}$ ж) $\frac{7}{15} - \frac{8}{25} = \frac{35}{75} - \frac{24}{75} = \frac{11}{75}$ з) $\frac{7}{45} - \frac{7}{60} = \frac{28}{180} - \frac{21}{180} = \frac{7}{180}$ Задание 6. а) $\frac{1}{6} + \frac{5}{9} + \frac{5}{6} + \frac{4}{9} = (\frac{1}{6} + \frac{5}{6}) + (\frac{5}{9} + \frac{4}{9}) = \frac{6}{6} + \frac{9}{9} = 1 + 1 = 2$ б) $\frac{2}{17} + \frac{3}{8} + \frac{5}{17} + \frac{10}{17} + \frac{5}{8} = (\frac{2}{17} + \frac{5}{17} + \frac{10}{17}) + (\frac{3}{8} + \frac{5}{8}) = \frac{17}{17} + \frac{8}{8} = 1 + 1 = 2$ в) $\frac{1}{12} + \frac{1}{16} + \frac{5}{12} + \frac{7}{16} = (\frac{1}{12} + \frac{5}{12}) + (\frac{1}{16} + \frac{7}{16}) = \frac{6}{12} + \frac{8}{16} = \frac{1}{2} + \frac{1}{2} = 1$ г) $\frac{3}{17} + \frac{4}{15} + \frac{1}{15} + \frac{14}{17} = (\frac{3}{17} + \frac{14}{17}) + (\frac{4}{15} + \frac{1}{15}) = \frac{17}{17} + \frac{5}{15} = 1 + \frac{1}{3} = \frac{4}{3} = 1\frac{1}{3}$