Реши уравнение: a) 2(x-2)² = 8

Решим уравнения: a) $2(x-2)^2 = 8$ $(x-2)^2 = 4$ $x-2 = \pm 2$ $x_1 = 4$, $x_2 = 0$ б) $\frac{1}{3}(1-x)^2 = \frac{1}{3}$ $(1-x)^2 = 1$ $1-x = \pm 1$ $x_1 = 0$, $x_2 = 2$ в) $3(x-5)^2 = 6$ $(x-5)^2 = 2$ $x-5 = \pm \sqrt{2}$ $x_1 = 5 + \sqrt{2}$, $x_2 = 5 - \sqrt{2}$ г) $10(x-3)^2 = 10$ $(x-3)^2 = 1$ $x-3 = \pm 1$ $x_1 = 4$, $x_2 = 2$ д) $\frac{2}{5}(x-10)^2 = \frac{4}{5}$ $(x-10)^2 = 2$ $x-10 = \pm \sqrt{2}$ $x_1 = 10 + \sqrt{2}$, $x_2 = 10 - \sqrt{2}$ е) $\frac{(x-1)^2}{3} = \frac{16}{3}$ $(x-1)^2 = 16$ $x-1 = \pm 4$ $x_1 = 5$, $x_2 = -3$ **Ответы:** a) $x_1 = 4$, $x_2 = 0$ б) $x_1 = 0$, $x_2 = 2$ в) $x_1 = 5 + \sqrt{2}$, $x_2 = 5 - \sqrt{2}$ г) $x_1 = 4$, $x_2 = 2$ д) $x_1 = 10 + \sqrt{2}$, $x_2 = 10 - \sqrt{2}$ е) $x_1 = 5$, $x_2 = -3