Вопрос:

Реши уравнения: а) 2/7*x = 2 2/7; б) 3/5*y = 2 9/10 - 1/5; в) 3/7*a + 2/5 = 1; г) 3 1/3 : k = 1 1/3 : 2; д) y : 1 1/2 = 2 1/3 * 1/3; е) 2/7*x + 3/7*x = 2 7/14; ж) m + 3/8*m = 1/4; з) y - 2/9*y = 4 2/3; и) 2/5*z + 2/3*z - 7/15*z = 2 1/2; к) 3 1/2 * (2/3*x + 4/7) = 2 1/3; л) (5/8*x - 1/5) * 3/4 = 3/4; м) 3/5*z + 2/3*z - 3 = 4/5.

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Ответ ассистента

Решаю уравнения: a) $\frac{2}{7}x = 2\frac{2}{7}$; $\frac{2}{7}x = \frac{16}{7}$; $x = \frac{16}{7} \cdot \frac{7}{2}$; $x = 8$; б) $\frac{3}{5}y = 2\frac{9}{10} - \frac{1}{5}$; $\frac{3}{5}y = \frac{29}{10} - \frac{2}{10}$; $\frac{3}{5}y = \frac{27}{10}$; $y = \frac{27}{10} \cdot \frac{5}{3}$; $y = \frac{9}{2} = 4.5$; в) $\frac{3}{7}a + \frac{2}{5} = 1$; $\frac{3}{7}a = 1 - \frac{2}{5}$; $\frac{3}{7}a = \frac{3}{5}$; $a = \frac{3}{5} \cdot \frac{7}{3}$; $a = \frac{7}{5} = 1.4$; г) $3\frac{1}{3} : k = 1\frac{1}{3} : 2$; $\frac{10}{3} : k = \frac{4}{3} : 2$; $\frac{10}{3} : k = \frac{4}{6}$; $k = \frac{10}{3} : \frac{4}{6}$; $k = \frac{10}{3} \cdot \frac{6}{4}$; $k = 5$; д) $y : 1\frac{1}{2} = 2\frac{1}{3} \cdot \frac{1}{3}$; $y : \frac{3}{2} = \frac{7}{3} \cdot \frac{1}{3}$; $y : \frac{3}{2} = \frac{7}{9}$; $y = \frac{7}{9} \cdot \frac{3}{2}$; $y = \frac{7}{6}$; е) $\frac{2}{7}x + \frac{3}{7}x = 2\frac{7}{14}$; $\frac{5}{7}x = \frac{35}{14}$; $x = \frac{35}{14} \cdot \frac{7}{5}$; $x = \frac{7}{2} = 3.5$; ж) $m + \frac{3}{8}m = \frac{1}{4}$; $\frac{11}{8}m = \frac{1}{4}$; $m = \frac{1}{4} \cdot \frac{8}{11}$; $m = \frac{2}{11}$; з) $y - \frac{2}{9}y = 4\frac{2}{3}$; $\frac{7}{9}y = \frac{14}{3}$; $y = \frac{14}{3} \cdot \frac{9}{7}$; $y = 6$; и) $\frac{2}{5}z + \frac{2}{3}z - \frac{7}{15}z = 2\frac{1}{2}$; $\frac{6}{15}z + \frac{10}{15}z - \frac{7}{15}z = \frac{5}{2}$; $\frac{9}{15}z = \frac{5}{2}$; $z = \frac{5}{2} \cdot \frac{15}{9}$; $z = \frac{25}{6}$; к) $3\frac{1}{2} \cdot (\frac{2}{3}x + \frac{4}{7}) = 2\frac{1}{3}$; $\frac{7}{2} \cdot (\frac{2}{3}x + \frac{4}{7}) = \frac{7}{3}$; $\frac{2}{3}x + \frac{4}{7} = \frac{7}{3} \cdot \frac{2}{7}$; $\frac{2}{3}x + \frac{4}{7} = \frac{2}{3}$; $\frac{2}{3}x = \frac{2}{3} - \frac{4}{7}$; $\frac{2}{3}x = \frac{14}{21} - \frac{12}{21}$; $\frac{2}{3}x = \frac{2}{21}$; $x = \frac{2}{21} \cdot \frac{3}{2}$; $x = \frac{1}{7}$; л) $(\frac{5}{8}x - \frac{1}{5}) \cdot \frac{3}{4} = \frac{3}{4}$; $\frac{5}{8}x - \frac{1}{5} = \frac{3}{4} \cdot \frac{4}{3}$; $\frac{5}{8}x - \frac{1}{5} = 1$; $\frac{5}{8}x = 1 + \frac{1}{5}$; $\frac{5}{8}x = \frac{6}{5}$; $x = \frac{6}{5} \cdot \frac{8}{5}$; $x = \frac{48}{25}$; м) $\frac{3}{5}z + \frac{2}{3}z - 3 = \frac{4}{5}$; $\frac{9}{15}z + \frac{10}{15}z = \frac{4}{5} + 3$; $\frac{19}{15}z = \frac{19}{5}$; $z = \frac{19}{5} \cdot \frac{15}{19}$; $z = 3$.

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