Преобразуй выражение в дробь и, если возможно, сократи её: 1) ax+b/bx + bx-a/ax

Конечно, давай помогу! 1) $\frac{ax+b}{bx} + \frac{bx-a}{ax} = \frac{a(ax+b) + b(bx-a)}{abx} = \frac{a^2x + ab + b^2x - ab}{abx} = \frac{a^2x + b^2x}{abx} = \frac{x(a^2 + b^2)}{abx} = \frac{a^2 + b^2}{ab}$ 2) $\frac{c+ny}{cy} - \frac{n-cy}{ny} = \frac{n(c+ny) - c(n-cy)}{cny} = \frac{nc + n^2y - nc + c^2y}{cny} = \frac{n^2y + c^2y}{cny} = \frac{y(n^2 + c^2)}{cny} = \frac{n^2 + c^2}{cn}$ 3) $\frac{m}{n} + \frac{n}{m} - \frac{(m-n)^2}{mn} = \frac{m^2 + n^2 - (m^2 - 2mn + n^2)}{mn} = \frac{m^2 + n^2 - m^2 + 2mn - n^2}{mn} = \frac{2mn}{mn} = 2$ 4) $\frac{(x-y)^2}{xy} - \frac{x}{y} - \frac{y}{x} = \frac{x^2 - 2xy + y^2}{xy} - \frac{x^2}{xy} - \frac{y^2}{xy} = \frac{x^2 - 2xy + y^2 - x^2 - y^2}{xy} = \frac{-2xy}{xy} = -2$ 5) $\frac{a+b}{2ab} + \frac{a+c}{2ac} + \frac{b+c}{2bc} = \frac{c(a+b) + b(a+c) + a(b+c)}{2abc} = \frac{ac + bc + ab + bc + ab + ac}{2abc} = \frac{2ac + 2bc + 2ab}{2abc} = \frac{2(ac + bc + ab)}{2abc} = \frac{ac + bc + ab}{abc}$ 6) $\frac{y+z}{yz} - \frac{x-y}{xy} - \frac{x-z}{xz} = \frac{x(y+z) - z(x-y) - y(x-z)}{xyz} = \frac{xy + xz - xz + yz - xy + yz}{xyz} = \frac{2yz}{xyz} = \frac{2}{x}$