Вычисли выражения из задания 270

Задание 270 1) $1 \frac{1}{3} + \frac{4}{5} = \frac{4}{3} + \frac{4}{5} = \frac{20}{15} + \frac{12}{15} = \frac{32}{15} = 2 \frac{2}{15}$ 2) $9 \frac{2}{11} - \frac{5}{5} = 9 \frac{2}{11} - 1 = 8 \frac{2}{11}$ 3) $13 \frac{9}{16} - \frac{9}{32} = 13 \frac{18}{32} - \frac{9}{32} = 13 \frac{9}{32}$ 4) $3 \frac{3}{28} + \frac{5}{14} = 3 \frac{3}{28} + \frac{10}{28} = 3 \frac{13}{28}$ 5) $14 \frac{7}{15} - 10 \frac{7}{10} = 4 + \frac{7}{15} - \frac{7}{10} = 4 + \frac{14}{30} - \frac{21}{30} = 4 - \frac{7}{30} = 3 \frac{30}{30} - \frac{7}{30} = 3 \frac{23}{30}$ 6) $3 \frac{1}{8} + 6 \frac{3}{16} = 9 + \frac{2}{16} + \frac{3}{16} = 9 \frac{5}{16}$ 7) $9 \frac{7}{25} - \frac{20}{7} = 9 \frac{7}{25} - 2 \frac{6}{7} = 7 + \frac{7}{25} - \frac{6}{7} = 7 + \frac{49}{175} - \frac{150}{175} = 7 - \frac{101}{175} = 6 + \frac{175}{175} - \frac{101}{175} = 6 \frac{74}{175}$ 8) $37 \frac{17}{42} - \frac{24}{17} = 37 \frac{17}{42} - 1 \frac{7}{24} = 36 + \frac{17}{42} - \frac{7}{24} = 36 + \frac{17*4}{42*4} - \frac{7*7}{24*7} = 36 + \frac{68}{168} - \frac{49}{168} = 36 \frac{19}{168}$ 9) $\frac{7}{9} - \frac{4}{15} = \frac{7*5}{9*5} - \frac{4*3}{15*3} = \frac{35}{45} - \frac{12}{45} = \frac{23}{45}$ 10) $\frac{9}{16} + \frac{7}{24} = \frac{9*3}{16*3} + \frac{7*2}{24*2} = \frac{27}{48} + \frac{14}{48} = \frac{41}{48}$ 11) $1 \frac{1}{3} + \frac{1}{6} + \frac{1}{4} = \frac{4}{3} + \frac{1}{6} + \frac{1}{4} = \frac{16}{12} + \frac{2}{12} + \frac{3}{12} = \frac{21}{12} = \frac{7}{4} = 1 \frac{3}{4}$ 12) $\frac{2}{5} + \frac{4}{15} - \frac{5}{9} = \frac{2*9}{5*9} + \frac{4*3}{15*3} - \frac{5*5}{9*5} = \frac{18}{45} + \frac{12}{45} - \frac{25}{45} = \frac{5}{45} = \frac{1}{9}$