Найди значение выражения.

Решаю примеры на вычитание смешанных чисел. a) $9\frac{11}{42} - 5\frac{11}{14} = 9\frac{11}{42} - 5\frac{33}{42} = (9-5) + \frac{11-33}{42} = 4 - \frac{22}{42} = 3 + 1 - \frac{22}{42} = 3 + \frac{42-22}{42} = 3\frac{20}{42} = 3\frac{10}{21}$ б) $15\frac{7}{24} - 11\frac{31}{36} = 15\frac{21}{72} - 11\frac{62}{72} = (15-11) + \frac{21-62}{72} = 4 - \frac{41}{72} = 3 + 1 - \frac{41}{72} = 3 + \frac{72-41}{72} = 3\frac{31}{72}$ в) $1\frac{121}{360} - \frac{41}{48} = 1\frac{121}{360} - \frac{307.5}{360} = (1-0) + \frac{121 - 307.5}{360} = 1 - \frac{186.5}{360} = \frac{360 - 186.5}{360} = \frac{173.5}{360} = \frac{347}{720}$ г) $5\frac{3}{11} - 4\frac{35}{66} = 5\frac{18}{66} - 4\frac{35}{66} = (5-4) + \frac{18-35}{66} = 1 - \frac{17}{66} = \frac{66-17}{66} = \frac{49}{66}$ д) $504\frac{11}{14} - 385\frac{15}{28} = 504\frac{22}{28} - 385\frac{15}{28} = (504 - 385) + \frac{22-15}{28} = 119 + \frac{7}{28} = 119\frac{1}{4}$ е) $90\frac{23}{60} - 48\frac{11}{12} = 90\frac{23}{60} - 48\frac{55}{60} = (90 - 48) + \frac{23-55}{60} = 42 - \frac{32}{60} = 41 + 1 - \frac{32}{60} = 41 + \frac{60-32}{60} = 41\frac{28}{60} = 41\frac{7}{15}$ ж) $120\frac{53}{102} - 107\frac{9}{34} = 120\frac{53}{102} - 107\frac{27}{102} = (120 - 107) + \frac{53-27}{102} = 13 + \frac{26}{102} = 13\frac{13}{51}$ з) $16\frac{19}{144} - 10\frac{7}{60} = 16\frac{95}{720} - 10\frac{84}{720} = (16 - 10) + \frac{95-84}{720} = 6 + \frac{11}{720} = 6\frac{11}{720}$ и) $105\frac{2}{17} - 3\frac{1}{13} = 105\frac{26}{221} - 3\frac{17}{221} = (105 - 3) + \frac{26-17}{221} = 102 + \frac{9}{221} = 102\frac{9}{221}$ к) $30\frac{7}{99} - 25\frac{5}{121} = 30\frac{847}{11979} - 25\frac{495}{11979} = (30 - 25) + \frac{847-495}{11979} = 5 + \frac{352}{11979} = 5\frac{352}{11979}$ л) $11\frac{21}{140} - 1\frac{11}{60} = 11\frac{63}{420} - 1\frac{77}{420} = (11 - 1) + \frac{63-77}{420} = 10 - \frac{14}{420} = 9 + 1 - \frac{14}{420} = 9 + \frac{420-14}{420} = 9\frac{406}{420} = 9\frac{203}{210}$ м) $4\frac{5}{246} - 3\frac{9}{492} = 4\frac{10}{492} - 3\frac{9}{492} = (4 - 3) + \frac{10-9}{492} = 1 + \frac{1}{492} = 1\frac{1}{492}$ н) $100\frac{7}{32} - 90\frac{2}{3} = 100\frac{21}{96} - 90\frac{64}{96} = (100 - 90) + \frac{21-64}{96} = 10 - \frac{43}{96} = 9 + 1 - \frac{43}{96} = 9 + \frac{96-43}{96} = 9\frac{53}{96}$