Реши примеры: 1) 5/27*(-18)

Конечно, давай решим эти примеры! 1) $\frac{5}{27} \cdot (-18) = \frac{5 \cdot (-18)}{27} = \frac{5 \cdot (-2)}{3} = -\frac{10}{3} = -3\frac{1}{3}$ 2) $(-24) \cdot \frac{11}{40} = \frac{(-24) \cdot 11}{40} = \frac{(-3) \cdot 11}{5} = -\frac{33}{5} = -6\frac{3}{5}$ 3) $(-2\frac{1}{2}) : 4 = (-\frac{5}{2}) : 4 = -\frac{5}{2} \cdot \frac{1}{4} = -\frac{5}{8}$ 4) $(-9) \cdot 3\frac{2}{9} = (-9) \cdot \frac{29}{9} = -29$ 5) $\frac{3}{34} \cdot (-\frac{17}{60}) = \frac{3 \cdot (-17)}{34 \cdot 60} = \frac{1 \cdot (-1)}{2 \cdot 20} = -\frac{1}{40}$ 6) $(-\frac{2}{9}) \cdot \frac{27}{6} = (-\frac{2}{9}) \cdot \frac{9}{2} = -1$ 7) $(-4\frac{1}{3}) \cdot \frac{6}{13} = (-\frac{13}{3}) \cdot \frac{6}{13} = -\frac{1}{1} \cdot \frac{2}{1} = -2$ 8) $\frac{9}{22} \cdot (-1\frac{5}{6}) = \frac{9}{22} \cdot (-\frac{11}{6}) = \frac{3}{2} \cdot (-\frac{1}{2}) = -\frac{3}{4}$ 9) $2\frac{1}{5} \cdot (-1\frac{1}{11}) = \frac{11}{5} \cdot (-\frac{12}{11}) = \frac{1}{5} \cdot (-12) = -\frac{12}{5} = -2\frac{2}{5}$ 10) $2\frac{29}{31} \cdot (-4\frac{10}{13}) = \frac{91}{31} \cdot (-\frac{62}{13}) = \frac{7}{1} \cdot (-\frac{2}{13}) = -\frac{14}{13} = -1\frac{1}{13}$