Ты просишь меня решить примеры на сложение, вычитание обыкновенных и смешанных дробей.

Конечно, давай решим эти примеры! 1. a) $7 + 2\frac{5}{8} = 7 + \frac{2 \cdot 8 + 5}{8} = 7 + \frac{21}{8} = 7 + 2\frac{5}{8} = 9\frac{5}{8}$; б) $9\frac{1}{9} + 20 = \frac{9 \cdot 9 + 1}{9} + 20 = \frac{82}{9} + 20 = 9\frac{1}{9} + 20 = 29\frac{1}{9}$; в) $64\frac{1}{7} + 4\frac{4}{7} = (64 + 4) + (\frac{1}{7} + \frac{4}{7}) = 68 + \frac{5}{7} = 68\frac{5}{7}$; г) $7\frac{5}{7} + 4\frac{1}{7} = (7 + 4) + (\frac{5}{7} + \frac{1}{7}) = 11 + \frac{6}{7} = 11\frac{6}{7}$. 2. a) $20\frac{3}{4} - 17 = (20 - 17) + \frac{3}{4} = 3 + \frac{3}{4} = 3\frac{3}{4}$; б) $13\frac{8}{11} - 5\frac{2}{11} = (13 - 5) + (\frac{8}{11} - \frac{2}{11}) = 8 + \frac{6}{11} = 8\frac{6}{11}$; в) $34\frac{7}{15} - 34 = (34 - 34) + \frac{7}{15} = 0 + \frac{7}{15} = \frac{7}{15}$; г) $29\frac{19}{23} - 7\frac{6}{23} = (29 - 7) + (\frac{19}{23} - \frac{6}{23}) = 22 + \frac{13}{23} = 22\frac{13}{23}$. 3. a) $14 - \frac{6}{9} = 13 + 1 - \frac{6}{9} = 13 + \frac{9}{9} - \frac{6}{9} = 13 + \frac{3}{9} = 13\frac{3}{9} = 13\frac{1}{3}$; б) $82 - \frac{7}{15} = 81 + 1 - \frac{7}{15} = 81 + \frac{15}{15} - \frac{7}{15} = 81 + \frac{8}{15} = 81\frac{8}{15}$; в) $5 - 4\frac{3}{4} = 5 - \frac{4 \cdot 4 + 3}{4} = 5 - \frac{19}{4} = 5 - 4\frac{3}{4} = \frac{5 \cdot 4}{4} - \frac{19}{4} = \frac{20}{4} - \frac{19}{4} = \frac{1}{4}$; г) $44 - 3\frac{8}{11} = 44 - \frac{3 \cdot 11 + 8}{11} = 44 - \frac{41}{11} = 44 - 3\frac{8}{11} = \frac{44 \cdot 11}{11} - \frac{41}{11} = \frac{484}{11} - \frac{41}{11} = \frac{443}{11} = 40\frac{3}{11}$. 4. a) $4\frac{4}{7} + 12\frac{5}{7} = (4 + 12) + (\frac{4}{7} + \frac{5}{7}) = 16 + \frac{9}{7} = 16 + 1\frac{2}{7} = 17\frac{2}{7}$; б) $9\frac{8}{15} + 6\frac{13}{15} = (9 + 6) + (\frac{8}{15} + \frac{13}{15}) = 15 + \frac{21}{15} = 15 + \frac{7}{5} = 15 + 1\frac{2}{5} = 16\frac{2}{5}$; в) $5\frac{4}{7} - 1\frac{5}{7} = (5 - 1) + (\frac{4}{7} - \frac{5}{7}) = 4 - \frac{1}{7} = 3 + 1 - \frac{1}{7} = 3 + \frac{7}{7} - \frac{1}{7} = 3 + \frac{6}{7} = 3\frac{6}{7}$; г) $4\frac{8}{15} - 2\frac{13}{15} = (4 - 2) + (\frac{8}{15} - \frac{13}{15}) = 2 - \frac{5}{15} = 2 - \frac{1}{3} = 1 + 1 - \frac{1}{3} = 1 + \frac{3}{3} - \frac{1}{3} = 1 + \frac{2}{3} = 1\frac{2}{3}$.