Ты просишь сократить дроби в заданиях 28-33

Задание 28: а) $\frac{4a^2}{6ac} = \frac{2a}{3c}$ б) $\frac{7x^2y}{21xy^2} = \frac{x}{3y}$ в) $\frac{56m^2n^5}{35mn^5} = \frac{8m}{5}$ г) $\frac{25p^4q}{100p^4q} = \frac{1}{4}$ Задание 29: а) $\frac{8^{16}}{16^{12}} = \frac{(2^3)^{16}}{(2^4)^{12}} = \frac{2^{48}}{2^{48}} = 1$ б) $\frac{81^{25}}{27^{33}} = \frac{(3^4)^{25}}{(3^3)^{33}} = \frac{3^{100}}{3^{99}} = 3$ Задание 30: а) $\frac{a(b-2)}{5(b-2)} = \frac{a}{5}$ б) $\frac{3(x+4)}{c(x+4)} = \frac{3}{c}$ в) $\frac{ab(y+3)}{a^2b(y+3)} = \frac{1}{a}$ г) Допущение: $\frac{12}{24} = \frac{1}{2}$ Задание 31: а) $\frac{3a+12b}{6ab} = \frac{3(a+4b)}{6ab} = \frac{a+4b}{2ab}$ б) $\frac{15b-20c}{10b} = \frac{5(3b-4c)}{10b} = \frac{3b-4c}{2b}$ в) $\frac{2a-4}{3(a-2)} = \frac{2(a-2)}{3(a-2)} = \frac{2}{3}$ г) $\frac{5x(y+2)}{6y+12} = \frac{5x(y+2)}{6(y+2)} = \frac{5x}{6}$ д) $\frac{a-3b}{a^2-3ab} = \frac{a-3b}{a(a-3b)} = \frac{1}{a}$ е) $\frac{3x^2+15xy}{x+5y} = \frac{3x(x+5y)}{x+5y} = 3x$ Задание 32: а) $\frac{y^2-16}{3y+12} = \frac{(y-4)(y+4)}{3(y+4)} = \frac{y-4}{3}$ б) $\frac{5x-15y}{x^2-9y^2} = \frac{5(x-3y)}{(x-3y)(x+3y)} = \frac{5}{x+3y}$ в) $\frac{(c+2)^2}{7c^2+14c} = \frac{(c+2)^2}{7c(c+2)} = \frac{c+2}{7c}$ г) $\frac{6cd-18c}{(d-3)^2} = \frac{6c(d-3)}{(d-3)^2} = \frac{6c}{d-3}$ д) $\frac{a^2+10a+25}{a^2-25} = \frac{(a+5)^2}{(a-5)(a+5)} = \frac{a+5}{a-5}$ е) $\frac{y^2-9}{y^2-6y+9} = \frac{(y-3)(y+3)}{(y-3)^2} = \frac{y+3}{y-3}$ Задание 33: а) $\frac{a^2-ab+b^2}{a^3+b^3} = \frac{a^2-ab+b^2}{(a+b)(a^2-ab+b^2)} = \frac{1}{a+b}$ б) $\frac{a^3-b^3}{a-b} = \frac{(a-b)(a^2+ab+b^2)}{a-b} = a^2+ab+b^2$ в) $\frac{(a+b)^3}{a^3+b^3} = \frac{(a+b)^3}{(a+b)(a^2-ab+b^2)} = \frac{(a+b)^2}{a^2-ab+b^2}$