Выполни вычисления: 5/11 + 1/11

Конечно, давай решим эти примеры вместе! 1. Вычислите: a) $\frac{5}{11} + \frac{1}{11} = \frac{5+1}{11} = \frac{6}{11}$ б) $\frac{3}{7} + \frac{1}{4} = \frac{3 \cdot 4}{7 \cdot 4} + \frac{1 \cdot 7}{4 \cdot 7} = \frac{12}{28} + \frac{7}{28} = \frac{12+7}{28} = \frac{19}{28}$ в) $\frac{3}{5} + \frac{2}{15} = \frac{3 \cdot 3}{5 \cdot 3} + \frac{2}{15} = \frac{9}{15} + \frac{2}{15} = \frac{9+2}{15} = \frac{11}{15}$ г) $\frac{3}{25} + \frac{2}{15} = \frac{3 \cdot 3}{25 \cdot 3} + \frac{2 \cdot 5}{15 \cdot 5} = \frac{9}{75} + \frac{10}{75} = \frac{9+10}{75} = \frac{19}{75}$ д) $1 - \frac{4}{15} = \frac{15}{15} - \frac{4}{15} = \frac{15-4}{15} = \frac{11}{15}$ e) $\frac{3}{5} - \frac{2}{5} = \frac{3-2}{5} = \frac{1}{5}$ ж) $\frac{11}{12} - \frac{3}{4} = \frac{11}{12} - \frac{3 \cdot 3}{4 \cdot 3} = \frac{11}{12} - \frac{9}{12} = \frac{11-9}{12} = \frac{2}{12} = \frac{1}{6}$ з) $\frac{5}{8} - \frac{5}{9} = \frac{5 \cdot 9}{8 \cdot 9} - \frac{5 \cdot 8}{9 \cdot 8} = \frac{45}{72} - \frac{40}{72} = \frac{45-40}{72} = \frac{5}{72}$ и) $\frac{5}{21} - \frac{3}{28} = \frac{5 \cdot 4}{21 \cdot 4} - \frac{3 \cdot 3}{28 \cdot 3} = \frac{20}{84} - \frac{9}{84} = \frac{20-9}{84} = \frac{11}{84}$ к) $1 - \frac{9}{32} = \frac{32}{32} - \frac{9}{32} = \frac{32-9}{32} = \frac{23}{32}$ 2. Вычислите: а) $\frac{5}{12} + (\frac{1}{12} + \frac{1}{4}) = \frac{5}{12} + (\frac{1}{12} + \frac{1 \cdot 3}{4 \cdot 3}) = \frac{5}{12} + \frac{1}{12} + \frac{3}{12} = \frac{5+1+3}{12} = \frac{9}{12} = \frac{3}{4}$ б) $\frac{1}{25} + \frac{3}{20} + \frac{4}{24} + \frac{1}{20} = \frac{1}{25} + \frac{3}{20} + \frac{1}{6} + \frac{1}{20} = \frac{1}{25} + \frac{1}{6} + \frac{3}{20} + \frac{1}{20} = \frac{1 \cdot 6}{25 \cdot 6} + \frac{1 \cdot 25}{6 \cdot 25} + \frac{3 \cdot 3}{20 \cdot 3} + \frac{1 \cdot 3}{20 \cdot 3} = \frac{6}{150} + \frac{25}{150} + \frac{9}{60} + \frac{3}{60} = \frac{31}{150} + \frac{12}{60} = \frac{31}{150} + \frac{2}{10} = \frac{31}{150} + \frac{2 \cdot 15}{10 \cdot 15} = \frac{31}{150} + \frac{30}{150} = \frac{31+30}{150} = \frac{61}{150}$ в) $\frac{3}{5} + \frac{5}{6} - \frac{7}{30} = \frac{3 \cdot 6}{5 \cdot 6} + \frac{5 \cdot 5}{6 \cdot 5} - \frac{7}{30} = \frac{18}{30} + \frac{25}{30} - \frac{7}{30} = \frac{18+25-7}{30} = \frac{36}{30} = \frac{6}{5} = 1\frac{1}{5}$ 3. Вычислите: а) $9\frac{4}{11} + 2 = 9 + \frac{4}{11} + 2 = 9 + 2 + \frac{4}{11} = 11 + \frac{4}{11} = 11\frac{4}{11}$ б) $5\frac{6}{13} + 4\frac{2}{13} = 5 + \frac{6}{13} + 4 + \frac{2}{13} = 5 + 4 + \frac{6}{13} + \frac{2}{13} = 9 + \frac{6+2}{13} = 9 + \frac{8}{13} = 9\frac{8}{13}$ в) $2\frac{5}{27} + \frac{17}{27} = 2 + \frac{5}{27} + \frac{17}{27} = 2 + \frac{5+17}{27} = 2 + \frac{22}{27} = 2\frac{22}{27}$ 4. Вычислите: а) $12\frac{7}{24} - 5 = 12 + \frac{7}{24} - 5 = 12 - 5 + \frac{7}{24} = 7 + \frac{7}{24} = 7\frac{7}{24}$ б) $5\frac{26}{43} - 4\frac{8}{43} = 5 + \frac{26}{43} - 4 - \frac{8}{43} = 5 - 4 + \frac{26}{43} - \frac{8}{43} = 1 + \frac{26-8}{43} = 1 + \frac{18}{43} = 1\frac{18}{43}$ в) $10\frac{28}{55} - \frac{13}{55} = 10 + \frac{28}{55} - \frac{13}{55} = 10 + \frac{28-13}{55} = 10 + \frac{15}{55} = 10 + \frac{3}{11} = 10\frac{3}{11}$