Выполни действия: a) $5\frac{1}{6} + 4\frac{3}{4}$

- a) $5\frac{1}{6} + 4\frac{3}{4} = 5 + \frac{1}{6} + 4 + \frac{3}{4} = 9 + \frac{1}{6} + \frac{3}{4} = 9 + \frac{2}{12} + \frac{9}{12} = 9 + \frac{11}{12} = 9\frac{11}{12}$ *Перевод: a) $5\frac{1}{6} + 4\frac{3}{4} = 5 + \frac{1}{6} + 4 + \frac{3}{4} = 9 + \frac{1}{6} + \frac{3}{4} = 9 + \frac{2}{12} + \frac{9}{12} = 9 + \frac{11}{12} = 9\frac{11}{12}$* - B) $\frac{3}{10} - \frac{4}{15} = \frac{9}{30} - \frac{8}{30} = \frac{1}{30}$ *Перевод: B) $\frac{3}{10} - \frac{4}{15} = \frac{9}{30} - \frac{8}{30} = \frac{1}{30}$* - г) $5 - 3\frac{2}{7} = 4\frac{7}{7} - 3\frac{2}{7} = 1\frac{5}{7}$ *Перевод: г) $5 - 3\frac{2}{7} = 4\frac{7}{7} - 3\frac{2}{7} = 1\frac{5}{7}$* - д) $\frac{4}{9} : \frac{3}{8} = \frac{4}{9} \cdot \frac{8}{3} = \frac{4 \cdot 8}{9 \cdot 3} = \frac{32}{27} = 1\frac{5}{27}$ *Перевод: д) $\frac{4}{9} : \frac{3}{8} = \frac{4}{9} \cdot \frac{8}{3} = \frac{4 \cdot 8}{9 \cdot 3} = \frac{32}{27} = 1\frac{5}{27}$* - e) $5\frac{8}{9} : 6\frac{5}{10} = \frac{53}{9} : \frac{65}{10} = \frac{53}{9} : \frac{13}{2} = \frac{53}{9} \cdot \frac{2}{13} = \frac{53 \cdot 2}{9 \cdot 13} = \frac{106}{117}$ *Перевод: e) $5\frac{8}{9} : 6\frac{5}{10} = \frac{53}{9} : \frac{65}{10} = \frac{53}{9} : \frac{13}{2} = \frac{53}{9} \cdot \frac{2}{13} = \frac{53 \cdot 2}{9 \cdot 13} = \frac{106}{117}$* - ж) $2\frac{6}{7} \cdot 1\frac{3}{7} = \frac{20}{7} \cdot \frac{10}{7} = \frac{20 \cdot 10}{7 \cdot 7} = \frac{200}{49} = 4\frac{4}{49}$ *Перевод: ж) $2\frac{6}{7} \cdot 1\frac{3}{7} = \frac{20}{7} \cdot \frac{10}{7} = \frac{20 \cdot 10}{7 \cdot 7} = \frac{200}{49} = 4\frac{4}{49}$* - з) $6\frac{3}{5} \cdot 10 = \frac{33}{5} \cdot 10 = \frac{33 \cdot 10}{5} = \frac{330}{5} = 66$ *Перевод: з) $6\frac{3}{5} \cdot 10 = \frac{33}{5} \cdot 10 = \frac{33 \cdot 10}{5} = \frac{330}{5} = 66$*