Реши примеры: a) $4\frac{11}{18} - 1\frac{4}{9}$;

a) $4\frac{11}{18} - 1\frac{4}{9} = \frac{4 \cdot 18 + 11}{18} - \frac{1 \cdot 9 + 4}{9} = \frac{72 + 11}{18} - \frac{9 + 4}{9} = \frac{83}{18} - \frac{13}{9} = \frac{83}{18} - \frac{13 \cdot 2}{9 \cdot 2} = \frac{83}{18} - \frac{26}{18} = \frac{83 - 26}{18} = \frac{57}{18} = \frac{19}{6} = 3\frac{1}{6}$ б) $(1\frac{1}{2})^3 - 2\frac{1}{4} \cdot 1\frac{1}{3} = (\frac{3}{2})^3 - \frac{9}{4} \cdot \frac{4}{3} = \frac{27}{8} - \frac{9 \cdot 4}{4 \cdot 3} = \frac{27}{8} - \frac{36}{12} = \frac{27}{8} - 3 = \frac{27}{8} - \frac{3 \cdot 8}{8} = \frac{27}{8} - \frac{24}{8} = \frac{27 - 24}{8} = \frac{3}{8}$ в) $18\frac{3}{14} + (12 - 6\frac{2}{3}) \cdot 1\frac{2}{7} = \frac{18 \cdot 14 + 3}{14} + (\frac{12 \cdot 3 - 6 \cdot 3 - 2}{3}) \cdot \frac{1 \cdot 7 + 2}{7} = \frac{252 + 3}{14} + (\frac{36 - 18 - 2}{3}) \cdot \frac{7 + 2}{7} = \frac{255}{14} + \frac{16}{3} \cdot \frac{9}{7} = \frac{255}{14} + \frac{16 \cdot 9}{3 \cdot 7} = \frac{255}{14} + \frac{144}{21} = \frac{255 \cdot 3}{14 \cdot 3} + \frac{144 \cdot 2}{21 \cdot 2} = \frac{765}{42} + \frac{288}{42} = \frac{765 + 288}{42} = \frac{1053}{42} = \frac{351}{14} = 25\frac{1}{14}$ г) $((1\frac{1}{4})^2 - \frac{5}{8}) \cdot 10\frac{2}{3} - 7\frac{1}{3} = ((\frac{5}{4})^2 - \frac{5}{8}) \cdot \frac{32}{3} - \frac{22}{3} = (\frac{25}{16} - \frac{5}{8}) \cdot \frac{32}{3} - \frac{22}{3} = (\frac{25}{16} - \frac{5 \cdot 2}{8 \cdot 2}) \cdot \frac{32}{3} - \frac{22}{3} = (\frac{25}{16} - \frac{10}{16}) \cdot \frac{32}{3} - \frac{22}{3} = \frac{15}{16} \cdot \frac{32}{3} - \frac{22}{3} = \frac{15 \cdot 32}{16 \cdot 3} - \frac{22}{3} = \frac{480}{48} - \frac{22}{3} = 10 - \frac{22}{3} = \frac{10 \cdot 3 - 22}{3} = \frac{30 - 22}{3} = \frac{8}{3} = 2\frac{2}{3}$ д) $1\frac{1}{22} \cdot 3\frac{2}{3} - (2\frac{5}{6} + 3\frac{5}{6} \cdot \frac{7}{23}) \cdot \frac{3}{5} = \frac{23}{22} \cdot \frac{11}{3} - (\frac{17}{6} + \frac{23}{6} \cdot \frac{7}{23}) \cdot \frac{3}{5} = \frac{23 \cdot 11}{22 \cdot 3} - (\frac{17}{6} + \frac{23 \cdot 7}{6 \cdot 23}) \cdot \frac{3}{5} = \frac{253}{66} - (\frac{17}{6} + \frac{7}{6}) \cdot \frac{3}{5} = \frac{253}{66} - \frac{24}{6} \cdot \frac{3}{5} = \frac{253}{66} - 4 \cdot \frac{3}{5} = \frac{253}{66} - \frac{12}{5} = \frac{253 \cdot 5}{66 \cdot 5} - \frac{12 \cdot 66}{5 \cdot 66} = \frac{1265}{330} - \frac{792}{330} = \frac{1265 - 792}{330} = \frac{473}{330} = 1\frac{143}{330}$ ж) $(2,5 - 1\frac{1}{6})^2 \cdot \frac{27}{32} - 1\frac{6}{13} = (2\frac{5}{10} - 1\frac{1}{6})^2 \cdot \frac{27}{32} - \frac{19}{13} = (2\frac{15}{30} - 1\frac{5}{30})^2 \cdot \frac{27}{32} - \frac{19}{13} = (1\frac{10}{30})^2 \cdot \frac{27}{32} - \frac{19}{13} = (1\frac{1}{3})^2 \cdot \frac{27}{32} - \frac{19}{13} = (\frac{4}{3})^2 \cdot \frac{27}{32} - \frac{19}{13} = \frac{16}{9} \cdot \frac{27}{32} - \frac{19}{13} = \frac{16 \cdot 27}{9 \cdot 32} - \frac{19}{13} = \frac{432}{288} - \frac{19}{13} = \frac{3}{2} - \frac{19}{13} = \frac{3 \cdot 13}{2 \cdot 13} - \frac{19 \cdot 2}{13 \cdot 2} = \frac{39}{26} - \frac{38}{26} = \frac{39 - 38}{26} = \frac{1}{26}$ з) $(3\frac{1}{3} - 2\frac{1}{12})^2 \cdot 0,64 + 2\frac{7}{15} = (3\frac{4}{12} - 2\frac{1}{12})^2 \cdot 0,64 + 2\frac{7}{15} = (1\frac{3}{12})^2 \cdot 0,64 + 2\frac{7}{15} = (1\frac{1}{4})^2 \cdot 0,64 + 2\frac{7}{15} = (\frac{5}{4})^2 \cdot 0,64 + 2\frac{7}{15} = \frac{25}{16} \cdot 0,64 + 2\frac{7}{15} = \frac{25}{16} \cdot \frac{64}{100} + 2\frac{7}{15} = \frac{25 \cdot 64}{16 \cdot 100} + 2\frac{7}{15} = \frac{1600}{1600} + 2\frac{7}{15} = 1 + 2\frac{7}{15} = 3\frac{7}{15}$