Вычисли значения выражений с дробями в заданиях 3 и 4

Привет! Давай помогу тебе с этими заданиями. Выглядят они немного сложно, но мы сейчас всё разберём по порядку. **Задание 3** 1) $1\frac{5}{36} + 5\frac{1}{9} = 1\frac{5}{36} + 5\frac{4}{36} = 6\frac{9}{36} = 6\frac{1}{4}$ 2) $1\frac{20}{32} + 3\frac{1}{2} = 1\frac{5}{8} + 3\frac{4}{8} = 4\frac{9}{8} = 5\frac{1}{8}$ 3) $2\frac{28}{35} + 6\frac{1}{8} = 2\frac{4}{5} + 6\frac{1}{8} = 2\frac{32}{40} + 6\frac{5}{40} = 8\frac{37}{40}$ 4) $1\frac{7}{16} + 2\frac{5}{25} = 1\frac{7}{16} + 2\frac{1}{5} = 1\frac{35}{80} + 2\frac{16}{80} = 3\frac{51}{80}$ 5) $1\frac{11}{20} + 10\frac{5}{8} = 1\frac{22}{40} + 10\frac{25}{40} = 11\frac{47}{40} = 12\frac{7}{40}$ 6) $3\frac{2}{15} - 1\frac{21}{36} = 3\frac{2}{15} - 1\frac{7}{12} = 3\frac{8}{60} - 1\frac{35}{60} = 2\frac{68}{60} - 1\frac{35}{60} = 1\frac{33}{60} = 1\frac{11}{20}$ 7) $9\frac{1}{4} - 1\frac{8}{25} = 9\frac{25}{100} - 1\frac{32}{100} = 8\frac{125}{100} - 1\frac{32}{100} = 7\frac{93}{100}$ 8) $2\frac{1}{4} - 3\frac{2}{5} = 2\frac{5}{20} - 3\frac{8}{20} = -1\frac{3}{20}$ 9) $1\frac{30}{32} - 2\frac{3}{4} = 1\frac{15}{16} - 2\frac{3}{4} = 1\frac{15}{16} - 2\frac{12}{16} = -1\frac{3}{16}$ 10) $3\frac{19}{24} - 1\frac{3}{30} = 3\frac{19}{24} - 1\frac{1}{10} = 3\frac{95}{120} - 1\frac{12}{120} = 2\frac{83}{120}$ 11) $6\frac{1}{4} * 2\frac{9}{10} = \frac{25}{4} * \frac{29}{10} = \frac{25 * 29}{4 * 10} = \frac{725}{40} = \frac{145}{8} = 18\frac{1}{8}$ 12) $3\frac{1}{6} * 3\frac{9}{12} = \frac{19}{6} * \frac{45}{12} = \frac{19 * 45}{6 * 12} = \frac{855}{72} = \frac{285}{24} = \frac{95}{8} = 11\frac{7}{8}$ 13) $2\frac{1}{20} : 1\frac{12}{13} = \frac{41}{20} : \frac{25}{13} = \frac{41}{20} * \frac{13}{25} = \frac{41 * 13}{20 * 25} = \frac{533}{500}$ 14) $6\frac{2}{7} : 2\frac{12}{14} = \frac{44}{7} : \frac{40}{14} = \frac{44}{7} * \frac{14}{40} = \frac{44 * 14}{7 * 40} = \frac{616}{280} = \frac{154}{70} = \frac{22}{10} = \frac{11}{5} = 2\frac{1}{5}$ 15) $3\frac{3}{5} : 1\frac{5}{35} = \frac{18}{5} : \frac{40}{35} = \frac{18}{5} : \frac{8}{7} = \frac{18}{5} * \frac{7}{8} = \frac{18 * 7}{5 * 8} = \frac{126}{40} = \frac{63}{20} = 3\frac{3}{20}$ **Задание 4** 1) $(\frac{14}{20} + 2\frac{15}{27}) * 27 = (\frac{7}{10} + 2\frac{5}{9}) * 27 = (\frac{63}{90} + 2\frac{50}{90}) * 27 = 2\frac{113}{90} * 27 = \frac{293}{90} * 27 = \frac{293 * 27}{90} = \frac{7911}{90} = \frac{2637}{30} = \frac{879}{10} = 87\frac{9}{10}$ 2) $(2\frac{1}{2} - \frac{12}{15}) * \frac{1}{34} = (2\frac{1}{2} - \frac{4}{5}) * \frac{1}{34} = (2\frac{5}{10} - \frac{8}{10}) * \frac{1}{34} = 1\frac{7}{10} * \frac{1}{34} = \frac{17}{10} * \frac{1}{34} = \frac{17}{340} = \frac{1}{20}$ 3) $(2\frac{4}{10} + 1\frac{13}{20}) * \frac{4}{9} = (2\frac{8}{20} + 1\frac{13}{20}) * \frac{4}{9} = 3\frac{21}{20} * \frac{4}{9} = \frac{81}{20} * \frac{4}{9} = \frac{81 * 4}{20 * 9} = \frac{324}{180} = \frac{81}{45} = \frac{9}{5} = 1\frac{4}{5}$ 4) $(\frac{8}{16} - 3\frac{3}{18}) * 12 = (\frac{1}{2} - 3\frac{1}{6}) * 12 = (\frac{3}{6} - 3\frac{1}{6}) * 12 = -3\frac{2}{6} * 12 = -3\frac{1}{3} * 12 = -\frac{10}{3} * 12 = -\frac{10 * 12}{3} = -\frac{120}{3} = -40$ 5) $(1\frac{3}{20} + 2\frac{7}{10}) * \frac{3}{11} = (1\frac{3}{20} + 2\frac{14}{20}) * \frac{3}{11} = 3\frac{17}{20} * \frac{3}{11} = \frac{77}{20} * \frac{3}{11} = \frac{77 * 3}{20 * 11} = \frac{231}{220} = \frac{21}{20} = 1\frac{1}{20}$ 6) $1\frac{8}{16} : (4\frac{13}{14} + \frac{3}{7}) = 1\frac{1}{2} : (4\frac{13}{14} + \frac{6}{14}) = \frac{3}{2} : 4\frac{19}{14} = \frac{3}{2} : \frac{75}{14} = \frac{3}{2} * \frac{14}{75} = \frac{3 * 14}{2 * 75} = \frac{42}{150} = \frac{21}{75} = \frac{7}{25}$ 7) $1\frac{17}{34} : (8\frac{1}{6} + 2\frac{6}{24}) = 1\frac{1}{2} : (8\frac{1}{6} + 2\frac{1}{4}) = \frac{3}{2} : (8\frac{2}{12} + 2\frac{3}{12}) = \frac{3}{2} : 10\frac{5}{12} = \frac{3}{2} : \frac{125}{12} = \frac{3}{2} * \frac{12}{125} = \frac{3 * 12}{2 * 125} = \frac{36}{250} = \frac{18}{125}$ 8) $2\frac{11}{36} : (1\frac{3}{27} + 3\frac{10}{20}) = 2\frac{11}{36} : (1\frac{1}{9} + 3\frac{1}{2}) = 2\frac{11}{36} : (1\frac{2}{18} + 3\frac{9}{18}) = 2\frac{11}{36} : 4\frac{11}{18} = \frac{83}{36} : \frac{83}{18} = \frac{83}{36} * \frac{18}{83} = \frac{83 * 18}{36 * 83} = \frac{3}{2} = 1\frac{1}{2}$ 9) $2\frac{3}{5} : (1\frac{12}{30} - 1\frac{10}{27}) = 2\frac{3}{5} : (1\frac{2}{5} - 1\frac{10}{27}) = \frac{13}{5} : (\frac{7}{5} - \frac{37}{27}) = \frac{13}{5} : (\frac{189}{135} - \frac{185}{135}) = \frac{13}{5} : \frac{4}{135} = \frac{13}{5} * \frac{135}{4} = \frac{13 * 135}{5 * 4} = \frac{1755}{20} = \frac{351}{4} = 87\frac{3}{4}$ 10) $18\frac{1}{5} : (2\frac{12}{30} - 2\frac{5}{6}) = 18\frac{1}{5} : (2\frac{2}{5} - 2\frac{5}{6}) = \frac{91}{5} : (\frac{12}{5} - \frac{17}{6}) = \frac{91}{5} : (\frac{72}{30} - \frac{85}{30}) = \frac{91}{5} : (-\frac{13}{30}) = \frac{91}{5} * -\frac{30}{13} = \frac{91 * -30}{5 * 13} = \frac{2730}{65} = \frac{546}{13} = 42$ Надеюсь, теперь тебе стало понятнее, как решать такие примеры! Если что-то осталось неясным, не стесняйся спрашивать.