Найди значение числового выражения: 1/120 + 4/15

a) $\frac{1}{120} + \frac{4}{15} = \frac{1}{120} + \frac{32}{120} = \frac{33}{120} = \frac{11}{40}$ б) $5\frac{3}{8} + 4\frac{5}{6} = \frac{43}{8} + \frac{29}{6} = \frac{129}{24} + \frac{116}{24} = \frac{245}{24} = 10\frac{5}{24}$ в) $5\frac{4}{9} - 1\frac{2}{3} = \frac{49}{9} - \frac{5}{3} = \frac{49}{9} - \frac{15}{9} = \frac{34}{9} = 3\frac{7}{9}$ г) $7\frac{3}{5} - (1\frac{2}{9} + 2\frac{3}{5}) = 7\frac{3}{5} - (1\frac{2}{9} + 2\frac{3}{5}) = \frac{38}{5} - (\frac{11}{9} + \frac{13}{5}) = \frac{38}{5} - (\frac{55}{45} + \frac{117}{45}) = \frac{38}{5} - \frac{172}{45} = \frac{342}{45} - \frac{172}{45} = \frac{170}{45} = \frac{34}{9} = 3\frac{7}{9}$ д) $\frac{8}{35} : \frac{49}{64} = \frac{8}{35} \cdot \frac{64}{49} = \frac{8 \cdot 64}{35 \cdot 49} = \frac{512}{1715}$ е) $10\frac{4}{5} \cdot 4\frac{3}{8} = \frac{54}{5} \cdot \frac{35}{8} = \frac{54 \cdot 35}{5 \cdot 8} = \frac{1890}{40} = \frac{189}{4} = 47\frac{1}{4}$ ж) $\frac{15}{22} : \frac{10}{77} = \frac{15}{22} \cdot \frac{77}{10} = \frac{15 \cdot 77}{22 \cdot 10} = \frac{1155}{220} = \frac{231}{44} = \frac{21}{4} = 5\frac{1}{4}$ з) $4\frac{6}{7} : 3\frac{9}{14} = \frac{34}{7} : \frac{51}{14} = \frac{34}{7} \cdot \frac{14}{51} = \frac{34 \cdot 14}{7 \cdot 51} = \frac{476}{357} = \frac{68}{51} = \frac{4}{3} = 1\frac{1}{3}$ и) $6\frac{5}{8} - 3\frac{1}{5} : \frac{7}{15} = \frac{53}{8} - \frac{16}{5} : \frac{7}{15} = \frac{53}{8} - \frac{16}{5} \cdot \frac{15}{7} = \frac{53}{8} - \frac{16 \cdot 15}{5 \cdot 7} = \frac{53}{8} - \frac{240}{35} = \frac{53}{8} - \frac{48}{7} = \frac{371}{56} - \frac{384}{56} = -\frac{13}{56}$ к) $-3,6 + 11,5 = 7,9$ л) $-19,1 - 5,7 = -24,8$ м) $-3,1 - (-5,9) = -3,1 + 5,9 = 2,8$ н) $-13,6 + 8,7 = -4,9$ о) $-3\frac{5}{12} + 1\frac{11}{18} = -\frac{41}{12} + \frac{29}{18} = -\frac{123}{36} + \frac{58}{36} = -\frac{65}{36} = -1\frac{29}{36}$ п) $-8\frac{11}{30} + 6,9 = -8\frac{11}{30} + 6\frac{9}{10} = -\frac{251}{30} + \frac{69}{10} = -\frac{251}{30} + \frac{207}{30} = -\frac{44}{30} = -\frac{22}{15} = -1\frac{7}{15}$ p) $1,6 - (-4,5) = 1,6 + 4,5 = 6,1$ с) $-135,2 : (-6,5) = 20,8$ р) $(-1\frac{7}{8}) \cdot 1\frac{1}{3} = -\frac{15}{8} \cdot \frac{4}{3} = -\frac{15 \cdot 4}{8 \cdot 3} = -\frac{60}{24} = -\frac{5}{2} = -2,5$ у) $1\frac{2}{3} : (-3\frac{1}{3}) = \frac{5}{3} : (-\frac{10}{3}) = \frac{5}{3} \cdot (-\frac{3}{10}) = -\frac{5 \cdot 3}{3 \cdot 10} = -\frac{15}{30} = -\frac{1}{2} = -0,5$