Вопрос:

Помоги мне выполнить действия с дробями в номере 1: 2/11 + 9/11

Фотография

Ответ ассистента

Конечно, давай помогу! Выполним действия с дробями. 1. $\frac{2}{11} + \frac{9}{11} = \frac{2+9}{11} = \frac{11}{11} = 1$ 2. $\frac{7}{15} + \frac{1}{15} + \frac{6}{15} = \frac{7+1+6}{15} = \frac{14}{15}$ 3. $\frac{12}{17} - \frac{5}{17} = \frac{12-5}{17} = \frac{7}{17}$ 4. $\frac{13}{23} - \frac{4}{23} - \frac{1}{23} = \frac{13-4-1}{23} = \frac{8}{23}$ 5. $3\frac{7}{12} + 5\frac{1}{12} = (3+5) + (\frac{7}{12} + \frac{1}{12}) = 8 + \frac{8}{12} = 8\frac{2}{3}$ 6. $2\frac{1}{2} + 7 = 2 + \frac{1}{2} + 7 = 9\frac{1}{2}$ 7. $4\frac{1}{6} + 10 = 14\frac{1}{6}$ 8. $7\frac{5}{7} + 4\frac{2}{7} = (7+4) + (\frac{5}{7} + \frac{2}{7}) = 11 + \frac{7}{7} = 11 + 1 = 12$ 9. $8\frac{9}{13} + 2\frac{5}{13} = (8+2) + (\frac{9}{13} + \frac{5}{13}) = 10 + \frac{14}{13} = 10 + 1\frac{1}{13} = 11\frac{1}{13}$ 10. $4 - \frac{3}{7} = \frac{4 \cdot 7}{7} - \frac{3}{7} = \frac{28}{7} - \frac{3}{7} = \frac{28-3}{7} = \frac{25}{7} = 3\frac{4}{7}$ 11. $5 - 3\frac{3}{5} = 5 - (3 + \frac{3}{5}) = 5 - 3 - \frac{3}{5} = 2 - \frac{3}{5} = \frac{2 \cdot 5}{5} - \frac{3}{5} = \frac{10}{5} - \frac{3}{5} = \frac{7}{5} = 1\frac{2}{5}$ 12. $4\frac{3}{5} - 1\frac{4}{5} = (4-1) + (\frac{3}{5} - \frac{4}{5}) = 3 - \frac{1}{5} = \frac{3 \cdot 5}{5} - \frac{1}{5} = \frac{15}{5} - \frac{1}{5} = \frac{14}{5} = 2\frac{4}{5}$ 13. $6\frac{14}{17} - 3\frac{2}{17} + 2\frac{5}{17} = (6-3+2) + (\frac{14}{17} - \frac{2}{17} + \frac{5}{17}) = 5 + \frac{17}{17} = 5 + 1 = 6$ 14. $8\frac{1}{5} + 2\frac{4}{5} - 3 = (8+2-3) + (\frac{1}{5} + \frac{4}{5}) = 7 + \frac{5}{5} = 7 + 1 = 8$ 15. $\frac{25}{33} + 5\frac{13}{33} - 4\frac{5}{33} = (5-4) + (\frac{25}{33} + \frac{13}{33} - \frac{5}{33}) = 1 + \frac{33}{33} = 1 + 1 = 2$ 16. $9\frac{1}{6} + 3\frac{5}{18} = 9 + \frac{1}{6} + 3 + \frac{5}{18} = 12 + \frac{1 \cdot 3}{6 \cdot 3} + \frac{5}{18} = 12 + \frac{3}{18} + \frac{5}{18} = 12 + \frac{8}{18} = 12 + \frac{4}{9} = 12\frac{4}{9}$ 17. $9\frac{1}{6} - 3\frac{5}{18} = 9 + \frac{1}{6} - 3 - \frac{5}{18} = 6 + \frac{1 \cdot 3}{6 \cdot 3} - \frac{5}{18} = 6 + \frac{3}{18} - \frac{5}{18} = 6 - \frac{2}{18} = 6 - \frac{1}{9} = \frac{6 \cdot 9}{9} - \frac{1}{9} = \frac{54}{9} - \frac{1}{9} = \frac{53}{9} = 5\frac{8}{9}$ 18. $10\frac{5}{8} - 2\frac{7}{16} = 10 + \frac{5}{8} - 2 - \frac{7}{16} = 8 + \frac{5 \cdot 2}{8 \cdot 2} - \frac{7}{16} = 8 + \frac{10}{16} - \frac{7}{16} = 8 + \frac{3}{16} = 8\frac{3}{16}$ 19. $5\frac{1}{8} + 14\frac{7}{12} = 5 + \frac{1}{8} + 14 + \frac{7}{12} = 19 + \frac{1 \cdot 3}{8 \cdot 3} + \frac{7 \cdot 2}{12 \cdot 2} = 19 + \frac{3}{24} + \frac{14}{24} = 19 + \frac{17}{24} = 19\frac{17}{24}$ 20. $8\frac{5}{9} + 3\frac{5}{6} = 8 + \frac{5}{9} + 3 + \frac{5}{6} = 11 + \frac{5 \cdot 2}{9 \cdot 2} + \frac{5 \cdot 3}{6 \cdot 3} = 11 + \frac{10}{18} + \frac{15}{18} = 11 + \frac{25}{18} = 11 + 1\frac{7}{18} = 12\frac{7}{18}$ 21. $5\frac{2}{3} - 3\frac{1}{5} = 5 + \frac{2}{3} - 3 - \frac{1}{5} = 2 + \frac{2 \cdot 5}{3 \cdot 5} - \frac{1 \cdot 3}{5 \cdot 3} = 2 + \frac{10}{15} - \frac{3}{15} = 2 + \frac{7}{15} = 2\frac{7}{15}$ 22. $12\frac{5}{12} - 8\frac{7}{18} = 12 + \frac{5}{12} - 8 - \frac{7}{18} = 4 + \frac{5 \cdot 3}{12 \cdot 3} - \frac{7 \cdot 2}{18 \cdot 2} = 4 + \frac{15}{36} - \frac{14}{36} = 4 + \frac{1}{36} = 4\frac{1}{36}$ 23. $3\frac{5}{16} - \frac{1}{4} - 1\frac{1}{16} = 3 + \frac{5}{16} - \frac{1}{4} - 1 - \frac{1}{16} = 2 + \frac{5}{16} - \frac{1 \cdot 4}{4 \cdot 4} - \frac{1}{16} = 2 + \frac{5}{16} - \frac{4}{16} - \frac{1}{16} = 2 + \frac{0}{16} = 2$ 24. $5\frac{11}{12} - 2\frac{1}{6} - 1\frac{1}{4} = 5 + \frac{11}{12} - 2 - \frac{1}{6} - 1 - \frac{1}{4} = 2 + \frac{11}{12} - \frac{1 \cdot 2}{6 \cdot 2} - \frac{1 \cdot 3}{4 \cdot 3} = 2 + \frac{11}{12} - \frac{2}{12} - \frac{3}{12} = 2 + \frac{6}{12} = 2 + \frac{1}{2} = 2\frac{1}{2}$ 25. $\frac{1}{8} + 1\frac{3}{5} + 2\frac{7}{8} = \frac{1}{8} + 1 + \frac{3}{5} + 2 + \frac{7}{8} = 3 + \frac{1}{8} + \frac{7}{8} + \frac{3}{5} = 3 + \frac{8}{8} + \frac{3}{5} = 3 + 1 + \frac{3}{5} = 4\frac{3}{5}$ 26. $2\frac{7}{9} - 1\frac{5}{18} + 5\frac{1}{2} = 2 + \frac{7}{9} - 1 - \frac{5}{18} + 5 + \frac{1}{2} = 6 + \frac{7 \cdot 2}{9 \cdot 2} - \frac{5}{18} + \frac{1 \cdot 9}{2 \cdot 9} = 6 + \frac{14}{18} - \frac{5}{18} + \frac{9}{18} = 6 + \frac{18}{18} = 6 + 1 = 7$ 27. $\frac{1}{3} \cdot \frac{2}{5} = \frac{1 \cdot 2}{3 \cdot 5} = \frac{2}{15}$ 28. $\frac{1}{2} \cdot \frac{4}{7} = \frac{1 \cdot 4}{2 \cdot 7} = \frac{4}{14} = \frac{2}{7}$ 29. $\frac{11}{12} \cdot \frac{4}{22} = \frac{11 \cdot 4}{12 \cdot 22} = \frac{44}{264} = \frac{1}{6}$ 30. $\frac{17}{26} \cdot \frac{13}{34} = \frac{17 \cdot 13}{26 \cdot 34} = \frac{221}{884} = \frac{1}{4}$ Надеюсь, теперь тебе стало понятнее, как решать такие примеры!

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