Вопрос:

Реши уравнения, представленные на изображении.

Фотография

Ответ ассистента

- $x - \frac{5}{8} = \frac{1}{8}$ $x = \frac{1}{8} + \frac{5}{8} = \frac{6}{8} = \frac{3}{4}$ - $x - \frac{6}{21} = \frac{1}{3}$ $x = \frac{1}{3} + \frac{6}{21} = \frac{7}{21} + \frac{6}{21} = \frac{13}{21}$ - $x \cdot \frac{13}{27} = \frac{7}{27}$ $x = \frac{7}{27} : \frac{13}{27} = \frac{7}{27} \cdot \frac{27}{13} = \frac{7}{13}$ - $x \cdot \frac{15}{29} = \frac{12}{29}$ $x = \frac{12}{29} : \frac{15}{29} = \frac{12}{29} \cdot \frac{29}{15} = \frac{12}{15} = \frac{4}{5}$ - $x : \frac{4}{9} = \frac{1}{9}$ $x = \frac{1}{9} \cdot \frac{4}{9} = \frac{4}{81}$ - $x - \frac{4}{9} = \frac{1}{9}$ $x = \frac{1}{9} + \frac{4}{9} = \frac{5}{9}$ - $x - \frac{3}{17} = \frac{4}{17}$ $x = \frac{4}{17} + \frac{3}{17} = \frac{7}{17}$ - $x \cdot \frac{12}{13} = \frac{6}{13}$ $x = \frac{6}{13} : \frac{12}{13} = \frac{6}{13} \cdot \frac{13}{12} = \frac{6}{12} = \frac{1}{2}$ - $x \cdot \frac{11}{17} = \frac{6}{17}$ $x = \frac{6}{17} : \frac{11}{17} = \frac{6}{17} \cdot \frac{17}{11} = \frac{6}{11}$ - $x : \frac{5}{6} = \frac{1}{6}$ $x = \frac{1}{6} \cdot \frac{5}{6} = \frac{5}{36}$ - $x + \frac{1}{7} = \frac{3}{7}$ $x = \frac{3}{7} - \frac{1}{7} = \frac{2}{7}$ - $x - \frac{4}{11} = \frac{7}{11}$ $x = \frac{7}{11} + \frac{4}{11} = \frac{11}{11} = 1$ - $x \cdot \frac{11}{12} = \frac{1}{12}$ $x = \frac{1}{12} : \frac{11}{12} = \frac{1}{12} \cdot \frac{12}{11} = \frac{1}{11}$ - $x \cdot \frac{13}{15} = \frac{2}{15}$ $x = \frac{2}{15} : \frac{13}{15} = \frac{2}{15} \cdot \frac{15}{13} = \frac{2}{13}$ - $x : \frac{7}{9} = \frac{2}{9}$ $x = \frac{2}{9} \cdot \frac{7}{9} = \frac{14}{81}$

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