Вычисли значение выражений в заданиях 310, 311 и 312

- 310.1) $7 - \sqrt{25} = 7 - 5 = 2$ - 310.2) $\sqrt{16-9} = \sqrt{7} \approx 2,65$ - 310.3) $4 \cdot \sqrt{0.01} = 4 \cdot 0.1 = 0.4$ - 310.4) $\frac{1}{3} \cdot \sqrt{0.81} = \frac{1}{3} \cdot 0.9 = 0.3$ - 310.5) $0.25 \cdot \sqrt{0.25} = 0.25 \cdot 0.5 = 0.125$ - 311.1) $2^3 + 5\sqrt{16} = 8 + 5 \cdot 4 = 28$ - 311.2) $3\sqrt{121} - 2\sqrt{144} = 3 \cdot 11 - 2 \cdot 12 = 33 - 24 = 9$ - 311.3) $2\sqrt{3 \cdot 27} - 6\sqrt{2 \cdot 18} = 2\sqrt{81} - 6\sqrt{36} = 2 \cdot 9 - 6 \cdot 6 = 18 - 36 = -18$ - 311.4) $\sqrt{2^2 + 3 \cdot 7} = \sqrt{4 + 21} = \sqrt{25} = 5$ - 311.5) $\sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5$ - 311.6) $\sqrt{17^2 - 15^2} = \sqrt{289 - 225} = \sqrt{64} = 8$ - 312.1) При $a = -3$: $3\sqrt{10 - 2 \cdot (-3)} = 3\sqrt{10 + 6} = 3\sqrt{16} = 3 \cdot 4 = 12$. При $a = 3$: $3\sqrt{10 - 2 \cdot 3} = 3\sqrt{10 - 6} = 3\sqrt{4} = 3 \cdot 2 = 6$. При $a = 5$: $3\sqrt{10 - 2 \cdot 5} = 3\sqrt{10 - 10} = 3\sqrt{0} = 0$ - 312.2) При $x = 1$: $5\sqrt{6 \cdot 1 - 2} = 5\sqrt{4} = 5 \cdot 2 = 10$. При $x = \frac{1}{3}$: $5\sqrt{6 \cdot \frac{1}{3} - 2} = 5\sqrt{2 - 2} = 5\sqrt{0} = 0$. При $x = 3$: $5\sqrt{6 \cdot 3 - 2} = 5\sqrt{18 - 2} = 5\sqrt{16} = 5 \cdot 4 = 20$